The answer to your question:
1.88 moles Na is 43.22 grams
Hey there:
a) atomic mass:
Carbon =<span>12.0107 g/mol
</span>Hydrogen = <span>1.00794 g/mol
Oxygen = </span><span>15.9994 g/mol
</span>
Therefore:
C12H22O11 =
12 * 12.0107 + 1 * 1.00794 + 16 * 15.9994 => <span>342.29648 g/mol
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b) number of moles:
n = m / mm
n = 3.115 / </span><span>342.29648
n = 0.0091 moles
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hope this helps!</span>
Answer:
Explanation:
Cesium Lewis dot structure would look like this:
·Cs, because it only has one valence electron. But, since it has a plus, that means we lost an electron. So, we have to get rid of the dot and you have:
Answer:
O H C
Moles in 100g 3.33 6.65 3.33
Ratio 1.00 2.00 1.00
Possible empirical formula = 
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial Y - -
Change -X +X +X
Equilibrium Y-X X X
Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²
Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
X = 5.79 x 10⁻⁵ M
Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
= 5.79 x 10⁻⁵ mol/L
Molar mass of CaCO₃ = 100 g mol⁻¹
Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
= 5.79 x 10⁻³ g/L
