Because i minus (-5) will come out to neg -4. a positive plus an neg equals an neg
Answer:
5:51 P.M.
Step-by-step explanation:
You first add 36 and 10 which you get 46 then add the 46 to the total so, 46 + 5 is 51 so she will get back at 5:51 P.M
Answer:
The rate of decrease is: ![43.2mm^3/min](https://tex.z-dn.net/?f=43.2mm%5E3%2Fmin)
Step-by-step explanation:
Given
![l = 18mm](https://tex.z-dn.net/?f=l%20%3D%2018mm)
---- We used minus because the rate is decreasing
Required
Rate of decrease when: ![l = 18mm](https://tex.z-dn.net/?f=l%20%3D%2018mm)
The volume of the cube is:
![V = l^3](https://tex.z-dn.net/?f=V%20%3D%20l%5E3)
Differentiate
![\frac{dV}{dl} = 3l^2](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdl%7D%20%3D%203l%5E2)
Make dV the subject
![dV = 3l^2 \cdot dl](https://tex.z-dn.net/?f=dV%20%3D%203l%5E2%20%5Ccdot%20dl)
Divide both sides by dt
![\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%203l%5E2%20%5Ccdot%20%5Cfrac%7Bdl%7D%7Bdt%7D)
Given that:
and ![\frac{dl}{dt} = -0.8mm/min](https://tex.z-dn.net/?f=%5Cfrac%7Bdl%7D%7Bdt%7D%20%3D%20-0.8mm%2Fmin)
![\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%203%20%2A%20%2818mm%29%5E2%20%2A%20%28-0.8mm%2Fmin%29)
![\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%203%20%2A%2018%20%2A-0.8mm%5E3%2Fmin)
![\frac{dV}{dt} = -43.2mm^3/min](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20-43.2mm%5E3%2Fmin)
<em>Hence, the rate of decrease is: 43.2mm^3/min</em>
I think it it's 25. I don't know I have just checked that on calculator.
If you are converting, make the denomenator 100 for fractions or look at 2 decimal places for decimals. if you want to find a certain percentage for a total, make the total of the item 100% and from there find 1% and multiply to the wanted percentage