All categories

3 years ago

I need help finding y

Mathematics

2 answers:

kolezko [41]3 years ago

4 0

to solve for y, we must multiply by t on both side to get ride of the t in the denominator. By doing this, we will get:

${t}^{3}$

on the right side.

Subtracting 3, and we have successfully isolated y.

It would be impossible to get a quantitative value for y if we don't know the value of t.

Snowcat [4.5K]3 years ago

3 0

respuesta listsdafddfssdffd

You might be interested in

What is the first step in adding these equations to eliminate y? 5x+6y=9

elena-14-01-66 [18.8K]

multiply all terms in the second equation by 2 to get the coefficient on the y variable to be -6.

$2(4x-3y=8)\\8x-6y=16$

7 0

3 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Type SSS, SAS, ASA, SAA, or HL to describe these triangles.

GalinKa [24]

Answer:

Step-by-step explanation:

3 0

2 years ago

PLEASE HELP ME I NEED HELP NOW AND NO ONE IS ANSWERING

Oksanka [162]

All the choices are correct.

_____
In our base-10 number system, moving a digit one place to the left multiplies its value by 10. Moving it one place to the right multiplies its value by 1/10.

You know already that 1,000 has 10 times the value of 100, and 1/10 the value of 10,000.

4 0

3 years ago

Solve 2(x + 1) = 2x + 2. (1 point) ♡ 0 O All real numbers No solution 1

sattari [20]

Answer:

B. All real numbers

Step-by-step explanation:

2(x + 1) = 2x + 2

Distribute the 2 inside the parenthesis.

2x + 2 = 2x + 2

Since the two expressions are equal and will stay equal with any value, the answer to this question is All real numbers.

Example:

2(x + 1) = 2x + 2

2(5 + 1) = 2(5) + 2

2(6) = 10 + 2

12 = 12

2(x + 1) = 2x + 2

2(150 + 1) = 2(150) + 2

2(151) = 300 + 2

302 = 302

The expression is equal for any value put in x.

6 0

3 years ago