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stiks02 [169]
3 years ago
6

A teacher gives a test to two algebra classes. The first class has 18 students, and the second has 24 students. If the average f

or the first class is 84% and x is the overall average grade for all students, then which of the following statements is true? A) 84≤X≤93.1B) 42≤X≤92C) 36≤X≤93.1D) 36≤X≤92E) 42≤X≤84
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

The <em>C)</em> statement is true.

Explanation:

Let's call <em>x_1</em> the average for the first class and <em>x_2 </em>the average for the second class. The overall average <em>x</em> is then:

x=\frac{x_1*18+x_2*24}{18+24}\\x=\frac{84*18+x_2*24}{42}\\x=\frac{1512+x_2*24}{42}

Since the average is given by <em>Average=\frac{Sum of all values}{Amount of values}</em>. We can now calculate <em>x</em> assuming the maximun and minimun values of <em>x_2</em>, 2400 (which is 100 times 24) and 0 respectivly. That gives:

x=\frac{1512+2400}{42}\\x=93

for it's maximun value and

x=\frac{1512+0}{42}\\x=36

for it's minimun value. So we get that <em>x</em> is between 36% and 93%.

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3 0
3 years ago
Identify the bronsted-lowry acid and the bronsted-lowry base in this reaction on the left side of each of the following equation
Dahasolnce [82]

<u>Answer:</u> NH_4^+ is an acid, CN^- is a base, NH_3 is conjugate base and HCN is conjugate acid

<u>Explanation:</u>

According to Bronsted and Lowry's theory:

An acid is defined as a proton donor while a base is defined as a proton acceptor.

In a chemical reaction, an acid loses a proton to form a conjugate base while a base accepts a proton to form conjugate acid.

For the given chemical reaction:

NH_4^+(aq)+CN^-(aq)\rightleftharpoons HCN(aq)+NH_3(aq)

NH_4^+ is losing a proton thus it is an acid to form NH_3 which is its conjugate base

CN^- is gaining a proton thus it is a base to form HCN which is its conjugate acid

Hence, NH_4^+ is an acid, CN^- is a base, NH_3 is conjugate base and HCN is conjugate acid

7 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
Calculate the speed for a car that travels a distance of 125 miles in 2 hours’ time.
Serga [27]

Answer:

125 divided by 2 = about 62.5

62.5 mph

Explanation:

7 0
3 years ago
Ammonia and oxygen react to form nitrogen and water, like this:
Dima020 [189]

Answer:

1. A. Zero.

2. D. Greater than zero, and greater than the rate of the reverse reaction.

3. C. Greater than zero, and equal to the rate of the reverse reaction.

4. A. Some, but less than 237. mmol.

Explanation:

Before reactants are added in a system the rate of reaction is zero. This is because, the initial rate of reaction depends on the concentration of the reacting species in the system.

When the reactants are first added, the rate of forward reaction increases rapidly and is far greater than the rate of reverse reaction.

However, at equilibrium, the rate of forward reaction is equal to the rate of reverse reaction.

At equilibrium, some NH3 has been used and some will still remain in the system because the reaction is reversible.

8 0
3 years ago
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