You can see that each time x increases by 1, y increases by 5. This means that the coefficient of x is 5 (if you graphed it, the slope would be 5). To find what value to add at the end, you can look at what y is when x equals 0. In this case, that is -2 (on a graph, -2 would be the y-intercept).
Answer:
The LCM of 9, 12, and 24, is <em>72. </em>
Step-by-step explanation:
To find the answer you must figure out the factors of <em>each number</em>, and see which factor has the <em>same number.</em>
<u><em>Factors of 9: </em></u> <u><em>Factors of 12:</em></u><em> </em><u><em>Factors of 24: </em></u>
<em> 9 12 24</em>
<em> 18 24 48</em>
<em> 27 36 72</em>
<em> 36 48</em>
<em> 45 60</em>
<em> 54 72</em>
<em> 63</em>
<em> 72</em>
When we look at all these factors, none of them have the same number <em>except 72.</em> Since <em>all</em> of these factors have <em>72 in them</em>, this is the<em> </em>LCM of 9, 12, and 24.
Answer:
73 ,,,,,,,,,,,,,,,,,,,,,,,
3(n-8)
You make it so that the three is on the outside of the brakets and that you can FOIL to bring it back to how it used to be
1st attachment
Part A,
I would assume the triangles are similar so
6y=4y+18
minus 4y both sides
2y=18
divide 2
y=9
Part B
sub for y
6(9)=54
the angle is 54
2nd attachment
4. I actually forgot proofs, let me think
dunno this one
I would say cory is wrong
3rd attachment
5. since 8≠9, it is not a bisector of any sort nor is it equidistant from T and R
answer is point A is not on a bisector
4th attachment
it is not perpendicular in any way
if we assume that TXA=RXA, then the first and last options are right
5th attachment
7.
those 2 triangles are equal because of Side-angle-side
they have to be equal 2x=3x-5
minus 2x both sides
0=x-5
add 5
5=x
x=5
8.
it would be isocelseese
because the 2 sides are equal
