The LCD of 2/5, 3/2, and 1/2 is

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

the lowest number that 5 and 2 go into is 10 a quick way to find LCD is just to multiply the denominators and that just see if there is any smaller numbers

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A senior center bought 100 tickets to a play. The total cost was 1,250. What was the cost of one ticket

Sergeu [11.5K]

Answer:

12.50

Step-by-step explanation:

To find the cost of one ticket, take the total cost and divide by the number of tickets

cost of one ticket = 1250/100

= 12.50

4 0

3 years ago

3.3^(2x+1)-103^x+1=0 need value of x

photoshop1234 [79]

Answer:

The value of $x$ is approximately -1.531.

Step-by-step explanation:

Let $3.3^{2\cdot x + 1}-103^{x+1} = 0$ , we proceed to solve this expression by algebraic means:

1) $3.3^{2\cdot x + 1}-103^{x+1} = 0$ Given

2) $3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0$ $a^{b}\cdot a^{c} = a^{b+c}$

3) $(3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$

4) $(3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$ /Commutative property

5) $\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0$ Existence of multiplicative inverse/Definition of division/Modulative property/ $a^{b}\cdot a^{c} = a^{b+c}$