All categories

3 years ago

Write an equation in slope-intercept form for the line that passes through (4, -4) and is parallel to 3 + 4x = 2y – 9.

1 answer:

8 0

Slope intercept form: y=mx + b
the slope is m
find the slope of the parallel line, and insert that slope for m in the slope intercept form.
Then find where the line that passes through (4, -4) crosses the y-axis, and use the y-intercept for b in the slope equation.

You might be interested in

Evaluate a2b2c2 for a = 2, b = 3, and c = 4.

olchik [2.2K]

2(2)2(3)2(4)=192 because you're multiplying everything together in order to find your answer and also because the variables which are the letters represent the numbers that need to be multiplied idk if that made sense but that's the answer lol

6 0

3 years ago

Read 2 more answers

Let x be the ages of students in a class. Given the frequency distribution f(x) above, determine the following probabilities:.

lora16 [44]

Probabilities are used to determine the chances of events

The value of the probability P(x < 24) is 0.7895

<h3>How to calculate the probability P(x < 24)?</h3>

This is calculated as:

$P(x < 24) = \frac{n(x < 24)}{Total}$

So, we have:

$P(x < 24) = \frac{22 + 3 + 5}{22 + 3 + 5 + 4 + 4}$

Evaluate the sums

$P(x < 24) = \frac{30}{38}$

Evaluate the quotient

$P(x < 24) = 0.7895$

Hence, the value of the probability P(x < 24) is 0.7895

Read more about probabilities at:

brainly.com/question/9385303

8 0

2 years ago

Help please with this

Elena-2011 [213]

Negative reciprocals of each other

3 0

2 years ago

Simplify: 20(1/5x - 3/4)+9x

Goryan [66]

Simplified answer is: 13x - 15

7 0

2 years ago

Read 2 more answers

The distance between city A and B is 600 km. The first train left A and headed towards B at the speed of 60 km/hour. The secon

hoa [83]

$\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
A&d&60&t\\
B&600-d&v&t+3
\end{array}$

$\bf \textit{meaning}\implies 
\begin{cases}
d=(60)(t)
\\ \quad \\
600-d=(v)(t+3)\\
------------\\
d=\boxed{60t}\qquad thus
\\ \quad \\
600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"}
\end{cases}$

keep in mind, that "t" is the time when the train at A station, left towards B station

they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference

8 0

2 years ago