Answer:Here
I forgot how to do this. Please help!
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Let's say that the smallest is called "a"
We can re-write the question like this:
a+(a+1)+(a+2)+(a+3) = 174
4a+6=174
4a=168
a=42
Answer:
Step-by-step explanation:
Given that

To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector

At the particular point, r'(t) = (1,1,e)
Tangent vector = 
ii) Normal vector
T'(t) = 
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
= ![\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%26e%5Et%5C%5C0%260%26e%5Et%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%20e%5Et%28i-j%29)
Answer:
Step-by-step explanation:
Since all the angles of triangle add up to 180 degrees,
Missing angle +100 +43=180.
Let the missing angle be 'x'.
Then, x + 100 +43 =180
or, x + 143 = 180
or, x = 180 - 143 = 37 degrees
So, the next angle is 37 degrees