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3 years ago

Are these Correct if not can you tell what is wrong? Thnx

Physics

1 answer:

nadya68 [22]3 years ago

5 0

All the description given are correct.

Explanation:

The electronic components like a switch, cell, battery, resistor, variable resistor, lamp, fuse, voltmeter, ammeter, photoresistor, etc are given in be the box.
The electronic components are inevitable for a circuit to function hence knowing their function is also very important. The description for all of these are correct and to the point.
To add more to the description of fuse and photoresistor, the fuse is something which is used in the circuit to cut down the current if there is a short circuit. A photoresistor is sensitive to lights. It works with the presence of light.

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The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum

SVEN [57.7K]

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

$U_1 +K_1 = U_3 + K_3$

where

$U_1$ is the initial potential energy, at the highest position

$K_1$ is the initial kinetic energy, at the highest position

$U_3$ is the final potential energy, at the lowest position

$K_3$ is the final kinetic energy, at the lowest position

We are told that:

$U_1 = 10 J$ is the potential energy of the pendulum at the maximum height

$K_1 = 0$ (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

$U_3 = 0$ (potential energy is zero at the lowest position)

Therefore,

$K_3 = U_1 = 10 J$

Kinetic energy can be rewritten as

$K_3 = \frac{1}{2}mv^2$

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

$v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

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4 0

3 years ago

1.A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upwar

Charra [1.4K]

Answer:

1. t = 3.27 seconds

2. y = 147.3 m

Explanation:

Newton's Laws of Motions.

y = v₁t + 1/2 at²

a = (v₂-v₁)/t

where

y = the vertical distance travelled

v₁ = the initial velocity

v₂ = the final velocity

t = the time

a = the acceleration

final velocity is equal to 0.

So, v₂ = 0.

a = (v₂-v₁)/t

a = (0-30)/t

a = -30/t

plugin values into the first equation:

y = v₁t + 1/2 at²

49 = 30t + 1/2 (-30/t)t²

49 = 30t -15t

49 = 15 t

t = 49/15

t = 3.27 seconds

y = v₁t + 1/2 at²

a = -30/3.27

a = 9.2

y = 30(3.27) + 1/2(9.2) 3.27²

y = 147.3 m

6 0

4 years ago

Evelyn learns that a sound wave can be recorded electronically as an analog signal or as a digital signal. She investigates thes

Olin [163]

Answer:

I got the answer of yr question

but it is too long

brainly is not taking

5 0

3 years ago

Read 2 more answers

A capacitor in an LC oscillator experiences a maximum potential difference of 88V and a maximum energy of 2002 uJ. At a certain

VLD [36.1K]

Answer:

Explanation:

maximum energy of capacitor

E = 1/2 C V ²

C is capacitance of capacitor and V is potential difference

given V = 88 V

E = 2002 x 10⁻⁶ J

Putting the values

2002 x 10⁻⁶ = 1/2 x C x 88²

C = .517 x 10⁻⁶ F .

In the second case

Energy E = 125 x 10⁻⁶ J .

C = .517 x 10⁻⁶

V = ?

E = 1/2 C V ²

125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²

V² = 483.55

V = 21.98 V .

6 0

4 years ago

A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi

Dmitriy789 [7]

Answer:

$A = 0.081 \ m$

The value is $u = 0.2569 \ m/s$

Explanation:

From the question we are told that

The mass is $m = 0.750 \ kg$

The spring constant is $k = 17.5 \ N/m$

The instantaneous speed is $v = 39.0 \ cm/s= 0.39 \ m/s$

The position consider is x = 0.750A meters from equilibrium point

Generally from the law of energy conservation we have that

The kinetic energy induced by the hammer = The energy stored in the spring

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k * A^2$

Here a is the amplitude of the subsequent oscillations

=> $A = \sqrt{\frac{m * v^ 2 }{ k} }$

=> $A = \sqrt{\frac{0.750 * 0.39 ^ 2 }{17.5} }$

=> $A = 0.081 \ m$

Generally from the law of energy conservation we have that

The kinetic energy by the hammer = The energy stored in the spring at the point considered + The kinetic energy at the considered point

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k x^2 + \frac{1}{2} * m * u^2$

=> $\frac{1}{2} * 0.750 * 0.39^2 = \frac{1}{2} * 17.5* 0.750(0.081 )^2 + \frac{1}{2} * 0.750 * u^2$

=> $u = 0.2569 \ m/s$

3 0

3 years ago

Are these Correct if not can you tell what is wrong? Thnx​

Are these Correct if not can you tell what is wrong? Thnx