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mafiozo [28]
3 years ago
10

20. A car battery with a 12-V emf and an internal resistance of 0.050 Ω is being charged with a current of 60 A. Note that in th

is process, the battery is being charged. (a) What is the potential difference across its terminals? (b) At what rate is thermal energy being dissipated in the battery? (c) At what rate is electric energy being converted into chemical energy
Physics
1 answer:
topjm [15]3 years ago
6 0

Answer:

Part a)

V = 15 Volts

Part b)

P = 180 Watt

Part c)

Rate = 720 Watt

Explanation:

Part a)

When battery is in charging then the potential difference of the terminals of cell is given by

\Delta V = EMF + iR

here we know that

EMF = 12 volts

i = 60 A

r = 0.050 ohm

now we have

\Delta V = 12 + (0.050)(60) = 15 Volts

Part b)

Rate of thermal energy dissipated is the energy which is dissipating across the resistor

so here we have

P = i^2 R

P = (60^2)(0.05)

P = 180 Watt

Part c)

Rate at which Energy stored inside the cell is the rate of electrical energy that is converted into the chemical energy

Rate = EMF \times i

Rate = (12)(60)

Rate = 720 Watt

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Read 2 more answers
An 8.5 kg crate is pulled 5.1 m up a 30 degree incline by a rope angled 17 degrees above the incline. The tension in the rope is
Ulleksa [173]

Answer:

1. a W_t=746.63 J

  b E_p=212.415 J

  c W_n=183.96J

2. T_e=99.71J

Explanation:

a). The work done by the tension is:

W_t=T*dt

dt=\frac{5.1}{cos(17)}

W_t=140N*\frac{5.1}{cos(17)}

W_t=746.63 J

b). The work done potential of gravity

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c). The work done by the normal force

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2. The increase in thermal energy is:

T_e=F*d

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F_k=19.5N

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