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Luba_88 [7]
3 years ago
15

The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum

is 10kg, how fast is the pendulum moving at point (3)?
Physics
1 answer:
SVEN [57.7K]3 years ago
4 0

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

U_1 +K_1 = U_3 + K_3

where

U_1 is the initial potential energy, at the highest position

K_1 is the initial kinetic energy, at the highest position

U_3 is the final potential energy, at the lowest position

K_3 is the final kinetic energy, at the lowest position

We are told that:

U_1 = 10 J is the potential energy of the pendulum at the maximum height

K_1 = 0 (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

U_3 = 0 (potential energy is zero at the lowest position)

Therefore,

K_3 = U_1 = 10 J

Kinetic energy can be rewritten as

K_3 = \frac{1}{2}mv^2

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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A substance undergoing a physical change will still weigh the same even after the change. This is in accordance to the law of conservation of mass which states that mass is neither created nor destroyed. so an 8 g substance remains of the same weight even after undergoing a physical change.
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The law of conservation of momentum states that the total momentum of interacting objects does not
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Answer:

Law of conservation of momentum states that "The total momentum of an isolated system always remains constant"

Or

"In an isolated system the total momentum of the interacting bodies remains constant before and after collision or interaction".

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What is the frequency of a wave that has a wavelength of 20 cm and a speed of 10 m/s?
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If you look at the picture you will see how, but the answer is 0.5 Hz.

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4 years ago
A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be
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Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, A=1\ cm^2=0.0001\ m^2

Resistivity of gold wire, \rho=2.8\times 10^{-8}\ \Omega-m

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

R=\rho \dfrac{l}{A}

l=\dfrac{RA}{\rho}

l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0
3 years ago
A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When
malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
1 year ago
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