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Luba_88 [7]
3 years ago
15

The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum

is 10kg, how fast is the pendulum moving at point (3)?
Physics
1 answer:
SVEN [57.7K]3 years ago
4 0

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

U_1 +K_1 = U_3 + K_3

where

U_1 is the initial potential energy, at the highest position

K_1 is the initial kinetic energy, at the highest position

U_3 is the final potential energy, at the lowest position

K_3 is the final kinetic energy, at the lowest position

We are told that:

U_1 = 10 J is the potential energy of the pendulum at the maximum height

K_1 = 0 (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

U_3 = 0 (potential energy is zero at the lowest position)

Therefore,

K_3 = U_1 = 10 J

Kinetic energy can be rewritten as

K_3 = \frac{1}{2}mv^2

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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The data set that is most likely from the car equipped with ABS is :

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<u><em>Although the plots related to your question is missing attached below is the missing data.  </em></u>

The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.

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Learn more : brainly.com/question/4360615

7 0
3 years ago
When opening a door, you push on it perpendicularly with a force of 57.0 n at a distance of 0.470 m from the hinges. what torque
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3 years ago
The figure below shows regions of the electromagnetic
nika2105 [10]

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The frequency of the gamma rays is >3×10

19

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6 0
3 years ago
a pool ball leaves a 0.60 meter high table with an initial high table with an initial horizontal velocity of 2.4m/s. predict the
timurjin [86]

Ball leaves the table of height 0.60 m

Initial speed of the ball is in horizontal direction which is 2.4 m/s

Now here we can say that time taken by the ball to hit the ground will be given by kinematics equation in vertical direction

\Delta y = v_y*t + \frac{1}{2}at^2

here in y direction we can say

\Delta y  = 0.60 m

v_y = 0

a = 9.8 m/s^2 due to gravity

now from above equation we have

0.60 = 0 + \frac{1}{2}*9.8*t^2

t = 0.35 s

Now in the same time the distance that ball move in horizontal direction is given as

d = v_x* t

given that

v_x = 2.4 m/s

d = 2.4 * 0.35

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5 0
3 years ago
A car drives 16 miles south and then 12 miles west. what is the magnitude of the car’s displacement?
saw5 [17]

Answer:

Car's displacement is 20 miles

Explanation:

The shortest path covered by a particle is called its displacement. It is given that, a car drives 16 miles south and then 12 miles west.

From the attached figure, OA = 12 miles

OB = 16 miles

So, their resultant is equal to the displacement, i.e. AB. So,

AB=\sqrt{OA^2+OB^2}

AB=\sqrt{12^2+16^2}

AB = 20 miles

So, the car's displacement is 20 miles. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
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