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Lapatulllka [165]
4 years ago
10

The number of vacancies in some hypothetical metal increases by a factor of 5 when the temperature is increased from 1080 K to 1

170 K. Calculate the energy (in kJ/mol) for vacancy formation assuming that the density of the metal remains the same over this temperature range.
Physics
1 answer:
Elena L [17]4 years ago
6 0

Answer:

E = 15.7 KJ/mol

Explanation:

The number of vacancies in a metal is given by

      n = n₀ e^{-E/KT}

They tell us that

     n = 5 no

We replace

      5 n₀ = n₀   e^{-E/KT}

      -E / KT = ln 5

       E = KT ln 5

       E = 1,381 10⁻²³  1170 ln 5

        E = 2.6 10⁻²⁰ J

To take (J / mol) we multiply between Avogadro's number

        E = 2.6 10⁻²⁰ 6.022 10²³

        E = 1.57 10⁴ J / mol

        E = 15.7 KJ/mol

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Can the kinetic energy of an object be negative? Can the potential energy of an object be negative? Can a potential energy funct
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Answer:

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potential energy is a reference dependent quantity and it can be positive as well as negative both

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Explanation:

Kinetic energy of an object is given by the formula

KE = \frac{1}{2}mv^2

here we know that

m = mass of object that can not be negative

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so Kinetic energy is always positive

potential energy is given as the energy due to the virtue of the position of object

so it is

\Delta U = -\int F.dr

so potential energy is a reference dependent quantity and it can be positive as well as negative both

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4 years ago
(a) How many kilograms of water must evaporate from a 60.0-kg woman to lower their body temperature by 0.750ºC?
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Answer:

69.69 g

Explanation:

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Heat taken up by evaporating water

= 2260000 x m J

Heat lost by body

= mass x specific heat of body x drop in temperature

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4 years ago
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2.04 meters distance is traveled by the sled before stopping.

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The initial speed of the sled = 2 m/s

Coefficient of kinetic friction between sled and ice = 0.100

Let the distance the sled moves before it stops be d.

Gravity = 9.8 m/ s²

Let the initial kinetic energy sled be

= K _{i}

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The work done by the frictional force is,

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W _{f} = μ_{k}mgd

Work done by frictional force= Initial kinetic energy of the sled

W_{f} = K_{i}

μ_{k}mgd= \frac{1}{2} mv ^{2}

So, the distance traveled by the sled before stopping is

d= \frac{1mv ^{2} }{2 \:μ_{k}mg}

d= \frac{1v ^{2} }{2 \:μ_{k}g}

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d= 2.04 \: m

Therefore, the distance traveled by the sled before stopping is 2.04 meters.

To know more about work done, refer to the below link:

brainly.com/question/13662169

#SPJ4

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2 years ago
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