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scZoUnD [109]
4 years ago
6

8a-2(7a-3) as a simplified expression ?

Mathematics
1 answer:
STatiana [176]4 years ago
6 0

8a-2(7a-3)

Multiply the bracket by -2

(-2)(7a)=-14a

(-2)(-3)=6

8a-14a+6

-6a+6 or 6-6a

Answer: -6a+6 or 6-6a

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If -4 is a root of the equation x^2+px-4=0 and the equation x^2+px+q=0 has equal roots, find the value of p and q
zubka84 [21]

Answer:

p = 3, q = 2.5

Step-by-step explanation:

Given that x = - 4 is a root of the equation, then

(- 4)² - 4p - 4 = 0, that is

16 - 4p - 4 = 0

12 - 4p = 0 ( subtract 12 from both sides )

- 4p = - 12 ( divide both sides by - 4 )

p = 3

Also given that the equation x² + px + q = 0 has equal roots

Thus the value of the discriminant b² - 4ac = 0

Here a = 1, b = p and c = q, thus

p² - 4q = 0 ← substitute p = 3 from above into the equation

9 - 4q = 0 ( subtract 9 from both sides )

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8 0
4 years ago
The ordered pairs ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4 ) , ( 4 , 2 5 6 ) , ( 5 , 1 , 0 2 4 ) ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4
Annette [7]

Answer:

The rule is f(x) = 2^(2x).

Step-by-step explanation:

Note that 4 = 2^2, 16 = 4^2,  64 = 8^2, 256 = 16^2  and 1024 = 32^2

and the first numbers in the ordered pairs are 1 , 2 ,3, 4, 5

compare this with  2, 4 , 8, 16 , 32.

We see that the rule for this is 2^x  where x is the sequence number.

So the rule for the original ordered pairs is (2^x)^2.

= 2^2x.

3 0
3 years ago
Solve & Explain your Math thinking 12-7
Tom [10]

For this case we have the following subtraction:

12-7

We can rewrite the subtraction in an easier way.

We have then:

12-7 = 12 - (5 + 2)

Then, by doing associative property we have:

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Answer:

The value of the subtraction is given by:

12-7 = 5

4 0
3 years ago
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Elza [17]

Answer:

21 to 3

70 to 10

Step-by-step explanation:

28÷7 = 4

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70÷7 = 10

8 0
3 years ago
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sashaice [31]

Answer:

10) x = 8.12

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Step-by-step explanation:

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5 0
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