A projectile is fired horizontally from a gun that is 45.0m above flat ground, emerging from the gun with a speed of 250m/s? How
long does the projectile remain in the air? At what horizontal distance from the firing point does it strike the ground? What is the magnitude of the vertical component of its velocity as it strikes the ground?
1 answer:
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Answer:
Explanation:
I = Moment of inertia =
m = Mass of two atoms = 2m =
r = distance between axis and rotation mass
Moment of inertia of the system is given by
The distance between the atoms will be two times the distance between axis and rotation mass.
Therefore, the distance between the two atoms is
Answer:
The pressure is 6570 lbf/ft²
The temperature is 766 ⁰R
The velocity is 2746.7 ft/s
deflection angle behind the wave is 17.56⁰
Explanation:
Speed of air at initial condition:
γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.
initial mach number
then,
based on the values obtained, read off the following from table;
P₂/P₁ = 3.285
T₂/T₁ = 1.473
Mₙ₂ = 0.6355
Thus;
P₂ = 3.285P₁ = 3.285(2000) = 6570 lbf/ft²
T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R
Again; to determine the velocity and deflection angle, first we calculate the mach number.