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3 years ago

In an electric motor, the rotating coil of wires wrapped around an iron core is a(n)

1 answer:

4 0

Answer:Where’s the answers to choose from but ik the answer to dis bcs I had to do this question before it’s Armature.

Explanation:

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determine the greates possile acceleration of the 975 kg race car so that its front wheels do not leace the gorund

wolverine [178]

<u>Answer</u>:

The greatest possible acceleration of the car is $a_G= 6.78 m/s^2$

<u>Explanation</u>:

$N_A+N_B-Mg = 0$

$-N_Aa +N_B(b-a)- \mu_s N_Bh - \mu_s N_Ah = 0$

$0.8N_B +0.8N_A = 975a_G$

$N_A+N_B = 9564.75$ -------------(1)

$-N_A(1.82) + N_B(2.20 -1.82) -0.9N_B(0.55)-0.8N_A(0.55)=0$

$-N_A(1.82) +0.38 N_B -0.44N_B -0.44N_A=0$

$-2.26N_A -0.06N_B= 0$ ----------------(2)

Solving the equation (1) and(2)

$N_A + N_B = 9564.75$

$-2.26N_A-0.06N_B=0$

$N_A = -260.85N$

$N_B = 9825.60N$

$\mu_s N_B + \mu_s N_A = 975a_G$

$0.8(9825.60)+0.8(-260.85) = 975a_G$ $a_G=\frac{7651.8}{975}$ $a_G_1=7.4848m/s^2$

Next lets assume that the front wheels contact with the ground N_A = 0

$F_B = Ma_G$

$N_B = M_g$

$N_B - M_g = 0$

$N_B(b-a) –F_Bh = 0$

$F_B = 975a_G$

$N_B-975(9.8) = 0$

$N_B=9564.75N$

$9564.75(2.20 -1.82) -F_B(0.55)=0$

$\frac{3634.605}{0.55}=F_B$

$F_B = 6608.3$

$F_B = Ma_G$

$6608.3 = 975a_G$

$a_G = 6.7778 m/s^2$

$a_G_2 = 6.78m/s^2$

Choosing the critical case

$a_G = min(a_G_1 ,a_G_2)$

$a_G = min(7.848, 6.78)$

$a_G= 6.78 m/s^2$

3 0

4 years ago

Describe a positive and negative net force acting on an object

Artemon [7]

There are different forces acting on an object like nuclear force , gravitational force...plus external forces like friction and other..

net sum of all these is resultnat

8 0

3 years ago

A planet has a circular orbit around a star. It is a distance of 53,000,000 km from the centre of the star.

Kipish [7]

Answer:

it takes 365 days to revolve around the star(sun)

5 0

3 years ago

water vapor contained in a piston–cylinder assembly undergoes an isothermal expansion at 240°c from a pressure of 7 bar to a pre

mafiozo [28]

The ideal gas constant is a proportionality constant that is added to the ideal gas law to account for pressure (P), volume (V), moles of gas (n), and temperature (T) (R). R, the global gas constant, is 8.314 J/K-1 mol-1.

According to the Ideal Gas Law, a gas's pressure, volume, and temperature may all be compared based on its density or mole value.

The Ideal Gas Law has two fundamental formulas.

PV = nRT, PM = dRT.

P = Atmospheric Pressure

V = Liters of Volume

n = Present Gas Mole Number

R = 0.0821atmLmoL K, the Ideal Gas Law Constant.

T = Kelvin-degree temperature

M stands for Molar Mass of the Gas in grams Mol d for Gas Density in gL.

Learn more about Ideal gas law here-

brainly.com/question/28257995

#SPJ4

7 0

1 year ago

A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=Lacross a horizontal surfac

Tomtit [17]

Answer:

A) v = √[(F₀/m - μ₀) 2x + x2 / L] , b) v = √[2 (F₀ / m - μ₀) +1] L

Explanation:

For this exercise we will use Newton's second law

X axis

Fo - fr = ma

Y Axis

N - W = 0

N = mg

The equation for the force of friction is

fr = μ N

.fr = μ mg

Let's replace

Fo - μ mg = m a

a = Fo / m - μ g

They ask us the speed of the block, so we must use

a = dv / dt = dv/dx dx dt = dv/dx v

v dv = a dx

We replace

v dv = (F₀ / m - μ₀ (1- x/L)) dx

We integrate

∫v dv = F₀ / m ∫ dx - μ₀ ∫ dx + 1 / L ∫ x dx

½ v² = (F₀ / m - μ₀) x + 1 / L x² / 2

We evaluate from the lower limit, for x = 0 the speed is zero v = 0, to the upper limit x, v

½ v² = (F₀ / m - μ₀) x + 1 / 2L x²

v = √[(F₀ / m - μ₀) 2x + x2 / L]

Part B

The velocity for x = L

v = √(F₀ / m - μ₀) 2L + L2 / L

v = √[2 (F₀ / m - μ₀) +1] L

8 0

3 years ago