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KatRina [158]
3 years ago
5

A bullet with a mass ????=12.5 g and speed ????=86.4 m/s is fired into a wooden block with ????=113 g which is initially at rest

on a horizontal surface. The bullet is embedded into the block. The block-bullet combination slides across the surface for a distance ???? before stopping due to friction between the block and surface. The coefficients of friction are ????????=0.753 and ????????=0.659. (a) What is the speed (m/s) of the block-bullet combination immediately after the collision? (b) What is the distance d (m)?
Physics
1 answer:
skad [1K]3 years ago
4 0

Answer:

a) 8.61 m/s, b) 5.73 m

Explanation:

a) During the collision, momentum is conserved.

mv = (m + M) V

(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V

V = 8.61 m/s

b) After the collision, energy is conserved.

Kinetic energy = Work done by friction

1/2 (m + M) V² = F d

1/2 (m + M) V² = N μk d

1/2 (m + M) V² = (m + M) g μk d

1/2 V² = g μk d

d = V² / (2g μk)

d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)

d = 5.73 m

Notice we used the kinetic coefficient of friction.  That's the friction when an object is moving.  The static coefficient of friction is the friction on a stationary object.  Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.

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Answer:

Very hot during the day and very cold at night.

Explanation:

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3 0
3 years ago
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As, buoyant force is given as 671 N and volume is 0.0882 m^{3} and acceleration is known as 9.8 m/s^{2}. Then density is

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A 150 kg safe on frictionless casters is being raised at 1.20m to the bed of a truck using planks 4m long. The force needed to p
Vesnalui [34]
The only thing you need to know in order to solve this task is that <span>plank length (which is force x), should equal the increase in potential energy, so what we have now : (mass)* g * (height).
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3 0
3 years ago
If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?
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The volume of rain that fells in the field is simply given by the area of the field, which is

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h=5.0 mm

Therefore, the volume is

V=hA=(5 mm)(100 mm^2)=500 mm^3

7 0
4 years ago
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