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omeli [17]
3 years ago
6

Which of the following are NOT two of the best ways to StaySafe around electricity?

Physics
1 answer:
creativ13 [48]3 years ago
3 0

1) Sleeping with an electronic in charge right next to you.

2) Leaving a charger plugged in all the time especially near liquid substances.

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Stomach acid is a dilute solution of hydrochloric acid (HCl). In this case the word dilute means
vfiekz [6]
I think the correct answer would be that there are a relatively small number of moles of HCl present. Dilute would mean that there are very few solute particles dissolved as compared to the solvent particles in the solution. Hope this helps.
6 0
3 years ago
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The average diameter of one tennis ball in a package of three is 6.8 cm. Which of the following is the combined volume of all th
Crank

We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3

First, remember that for a sphere of diameter D, the volume is:

V = \frac{4}{3}*3.14*(\frac{D}{2})^3

Where 3.14 is pi.

Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:

V = \frac{4}{3}*3.14*(\frac{6.8cm}{2})^3 = 164.5 cm^3

Now, in 3 balls of tennis, the combined volume will be 3 times the above one, this is:

3*V = 3*164.5cm^3 = 493.7 cm^3

If you want to learn more about volumes, you can read:

brainly.com/question/10171109

4 0
2 years ago
In 'coin on card' experiment a smooth card is used. ​
KIM [24]

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

5 0
3 years ago
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Inside a television picture tube there is a build-up of electrons (charge of 1.602 × 10^–19 C) with an average spacing of 38.0 n
Brut [27]
The magnitude of electric field is produced by the electrons at a certain distance.

E = kQ/r²

where: 
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Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2

Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m

Substitue the given:
E = </span>\frac{( 1.602 x 10^{-19} )( 9.0x10_{9} )}{(38x10^{-9}) ^{2} }

E = 998.476 kN/C


8 0
3 years ago
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Please help me feel out this paper. Very hard for me to figure thu
Anastaziya [24]
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The velocity is pointed along the tangent line at all times (parallel to the edge of the circle at any point)
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