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3 years ago

6

Which of the following are NOT two of the best ways to StaySafe around electricity?

1 answer:

creativ13 [48]3 years ago

3 0

1) Sleeping with an electronic in charge right next to you.

2) Leaving a charger plugged in all the time especially near liquid substances.

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What phase are daughter cells in as a result of mitosis

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They are in interphase

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4 years ago

A boat is able to move through still water at 20m/s. It makes a round trip to.a town 3km upstream.If the river flows at 5m/s,the

marishachu [46]

Answer:

the answer is 320 seconds :)

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3 years ago

2. What is the least possible error encountered

AlekseyPX

Answer: b 0.5mm

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3 years ago

Read 2 more answers

The most soaring vocal melody is in Johann Sebastian Bach's Mass in B minor. In one section, the basses, tenors, altos, and sopr

solmaris [256]

Answer:

2.33651226158 m

Explanation:

From the question the required data is as follows

f = Frequency of the initial note = 146.8 Hz

v = Velocity of sound in air = 343 m/s

The wavelength of a wave is given by

$\lambda=\dfrac{v}{f}$

$\Rightarrow \lambda=\dfrac{343}{146.8}$

$\Rightarrow \lambda=2.33651226158\ m$

The wavelength of the initial note is 2.33651226158 m

3 0

3 years ago

dybincka [34]

Answer:

1. 218.55 N

2. $30.96^{o}$

3. $2.1 m/s^{2}$

Explanation:

Part 1;

Net force $F=mg sin \theta$ where m is mass, g is gravitational force and $\theta$ is the angle of inclination

$F= 46*9.8*sin 29^{o}= 218.55N$

Frictional force, $F_{r}$ is given by

$F_{r} = \mu_{s}mg cos \theta$ where $\mu_{s}$ is the coefficient of static friction

$F_{r} = 0.6*46*9.8 cos 29$

$F_{r}=236.57N$

Since $F_{r}>F$ , therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force $F_{s} = \mu_{s} mg cos \theta$

$mg sin \theta =\mu_{s} mg cos \theta$

$\mu_{s}= \frac {sin \theta}{cos \theta}$

$\mu_{s}= tan \theta$

The maximum angle of inclination $\theta = tan^{-1} \mu_{s}$

$\theta = tan^{-1} (0.6)$

$\theta= 30.96^{o}$

Part 3:

Net force on the object is given by

$ma = mg sin 38 - \mu_{k} mg cos 38$ where $\mu_{k}$ is the coefficient of kinetic friction

$a = g ( sin 38 - \mu_{k} cos 38 )$

= 9.8 ( sin 38 - (0.51) cos 38 )

= $2.1m/s^{2}$

7 0

4 years ago