Given: Mass m = 60 Kg
Weight W = 96 N
Required: Acceleration due to gravity, g = ?
Formula: W = mg
g = W/g
g = 96 Kg.m/s²/60 Kg (note: this is the derive unit for Newton "N")
g = 1.6 m/s²
Answer:
The answer is: all of the answers are correct.
Explanation:
Entropy is defined as the magnitude of the irreversibilities of a process. Entropy is the disorder of molecules within a system. If the system is closed, entropy is produced if the process is irreversible. If the system is subjected to expansions or energy transfer, the entropy increases.
A process is reversible if the system and its surroundings are returned to their initial states. In a quasi-static process it is characterized by being a reversible process in which there are no irreversibilities. The entropy in this system is constant in the system.
Answer:
2.51 m/s
Explanation:
Parameters given:
Angle, A = 33°
Mass, m = 90kg
Inclined distance, D = 2m
Force, F = 600N
Initial speed, u = 2.3m/s
From the relationship between work and kinetic energy, we know that:
Work done = change in kinetic energy
W = 0.5m(v² - u²)
We also know that work done is tẹ product of force and distance, hence, net work done will be the sum of the total work done by the force from the students and gravity.
Hence,
W = F*D*cosA - w*D*sinA
w = m*9.8 = weight
=> W = 600*2*cos33 - 90*9.8*2*sin33
W = 45.7J
=> 45.7 = 0.5*m*(v² - u²)
45.7 = 0.5*90*(v² - 2.3²)
45.7 = 45(v² - 5.29)
=> v² - 5.29 = 1.016
v² = 6.306
v = 2.51 m/s
The final velocity is 2.51 m/s
Summer does not start on the same day in every country on the earth
Ω=2*pi*f = 2*pi*50 = 314.16
Inductive reactance, ZL = jωL = j*314.16*0.15 = j42.12
Capacitance reactance, ZC = 1/(jωC) =1/(j*314.16*0.005) = -j0.64
Impendance, Z = V/I = 240/0.1 = 2400
Now,
Z=R+j(ZL+ZC) => 2400 = R+ j(45.12-0.64) => 2400 = R + j44.48
Additionally,
2400^2 = R^2+44.48^2 => R = Sqrt (2400^2-44.48^2) = 2399.58 ohms.
Phase angle = arctan (44.48/2399.58) = 1.06°
