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Andreyy89
3 years ago
9

What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m

if the waves are to travel at 28.0 m/s ?
Physics
1 answer:
pychu [463]3 years ago
6 0

Complete question:

A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?

Answer:

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

Explanation:

Velocity = Frequency  X wavelength

V = Fλ ⇒ F = V/λ

F = 28/0.6 = 46.67 Hz

Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s

Average power supplied to the rope will be calculated as follows

P_{avg} =\frac{1}{2} \mu \omega^2 A^2 V

where;

ω is the angular frequency

A is the amplitude

V is the velocity

μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m

P_{avg} =\frac{1}{2} ( 0.0348)(93.34 \pi )^2 (0.2)^2 (28) = 1676.159 watts

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

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600,000,000 degree C

Explanation:

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A uniform magnetic field is perpendicular to the plane of a circular loop of diameter 13 cm formed from wire of diameter 2.6 mm
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Answer:

Rate of change of magnetic field is 3.466\times 10^3T/sec        

Explanation:

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Length of the circular loop L=2\pi r=2\times 3.14\times 0.065=0.4082m

Wire is made up of diameter of 2.6 mm

So radius r=\frac{2.6}{2}=1.3mm=0.0013m

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Resistivity of wire \rho =2.18\times 10^{-8}m

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Current is given i = 11 A

So emf  e=11\times 1.67\times 10^{-3}=0.0183volt

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0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}

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3 years ago
A stationary 90 kg baseball pitcher throws a 0.15 kg baseball forward
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From the question we are told that

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3 years ago
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