Answer:
No, its not reasonable.
Explanation:
The substance that is to be dissolved is known as solute. The substance that is dissolving is known as solvent.
The amount of solvent in the mixture should be greater than that of solute.
Suppose we are taking a solvent in a beaker and we are continuously adding solute in it. Initially the solute dissolve quickly. At some point the solute stops dissolving in the solvent. This is known as saturation point of the solvent. After saturation point if solute is added further it does not dissolve in the solvent.
So, its not possible to dissolve 12.8 g of one substance in 11 g of another.
Answer:
S = Vo t + 1/2 a t^2 distance traveled
t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec time to stop
S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m distance traveled
Answer:
6227.866 N
Explanation:
F = G . m(goku) . m(planet) / d²
F = 6.674 x 10-¹¹ x 62 x 1.458 . 10¹⁵ / 31²
F = 6227.866 N
We have all the charges for q1, q2, and q3.
Since k = 8.988x10^2, and N=m^2/c^2
F(1) = F (2on1) + F (3on1)
F(2on1) = k |q1 q2| / r(the distance between the two)^2
k^ | 3x10^-6 x -5 x 10^-6 | / (.2m)^2
F(2on1) = 3.37 N
Since F1 is 7N,
F(1) = F (2on1) + F (3on1)
7N = 3.37 N + F (3on1)
Since it wil be going in the negative direction,
-7N = 3.37 N + F (3on1)
F(3on1) = -10.37N
F(3on1) = k |q1 q3| / r(the distance between the two)^2
r^2 x F(3on1) = k |q1 q3|
r = sqrt of k |q1 q3| / F(3on1)
= .144 m (distance between q1 and q3)
0 - .144m
So it's located in -.144m
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