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MrRa [10]
3 years ago
13

Why can't helium bond with hydrogen?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
8 0
Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
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PLEASE HELP ASAP, WILL GIVE BRANLIEST!!
sergejj [24]

Answer:so that they may not get confused in which container did they place which chemical since some chemicals are simmilar in colour

Explanation:

6 0
3 years ago
Which of the following geological features can form at a subduction zone?
saw5 [17]

D

This feature is formed at destructive boundaries where the denser plate (usually the oceanic plate) is subducted underneath the less dense plate (usually the continental plate).

Explanation:

the stress in the boundary between the two plates causes them to warp at the boundary forming a trench. This forced bending and the friction between the two plates (remember tectonic plates are very rugged) causes fissures to develop at the boundary. As the denser plate dives into the mantle, it begins to melt and the molten rock rises through the fissures. The magma erupts at the surface in several fissures forming volcanic mountains ranges along the convergent boundary.

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3 0
4 years ago
A student has 540.0 mL of a 0.1035 M aqueous solution of Na2CrO4 to use in an experiment. She accidentally leaves the container
yulyashka [42]

Answer:

The chemical formula of this residue: Na_2CrO_4.10H_2O

Explanation:

Mass of residue = 19.12

Let the formula of the residue be Na_2CrO_4.xH_2O

Moles of residue: n

n=\frac{19.12}{162 g/mol+x\times 18 g/mol}

Moles of sodium chromate = n'

Molarity of sodium chromate = 0.1035 M

Volume of sodium chromate solution = 540.0 mL = 0.540 L

1 mL = 0.001 L

Concentration=\frac{moles}{Volume(L)}

0.1035 M=\frac{n}{0.540 L}

n'=0.1035 M\times 0.540 L=0.05589 mol

Na_2CrO_4+xH_2O\rightarrow Na_2CrO_4.xH_2O

According to reaction,1 mole of  Na_2CrO_4 gives 1 mole ofNa_2CrO_4.xH_2O

So, n = n'

\frac{19.12}{162 g/mol+x\times 18 g/mol}=0.05589 mol

x = 10

The chemical formula of this residue: Na_2CrO_4.10H_2O

8 0
4 years ago
What is the general formula of alkene?
Svetradugi [14.3K]

The general formula for the alkenes is C nH 2n

8 0
3 years ago
Page 705 #12/#13: Use the changes in oxidation numbers to identify which atom is oxidized, reduced, the oxidizing agent, and the
guapka [62]

Concepts to understand before solving:

-Oxygen is ALWAYS reduced

-OIL- Oxidation Is Loss of electrons

-RIG- Reduction Is Gain of electrons

-the element that is oxidized is the reducing agent

-the element that is reduced is the oxidizing agent

A. 2H2 + O2 —> 2H2O

O is reduced, making it the oxidizing agent

H is oxidized, making it the reducing agent

B. 2KNO3 —> 2KNO2 + O2

O is reduced, making it the oxidizing agent

KNO is oxidized, making it the reducing agent

7 0
4 years ago
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