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madam [21]
3 years ago
12

Alcl3+Na =NaCl+ Al .did Al change oxidation number

Chemistry
1 answer:
saul85 [17]3 years ago
5 0

Answer:

yes it is ( From +3 to 0 )

Explanation:

If this is the balanced equation:

AlCl3     +    3Na ——>    3NaCl      +      Al

Al      Cl        3Na             Na     Cl            Al

+3     -3        0                    +1       -1            0

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zhenek [66]

with what?..................

7 0
2 years ago
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
Hot, molten rock deep below Earth’s surface is called lava mantle rock parent rock magma
Rashid [163]

Answer:

I think it is Magma

6 0
3 years ago
What is the abbreviation for the element with atomic number 11?
VikaD [51]

Answer:

Sodium (Na) has atomic number 11.

5 0
3 years ago
Read 2 more answers
The total volume required to reach the endpoint of a titration required more than the 50 mL total volume of the buret. An initia
Margaret [11]

Answer:

The endpoint volume is 50.52 ±  0.14 mL

Explanation:

In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:

V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)

V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL

V = 50.52 ±  0.14 mL

It is necessary to consider the sum of the errors too.

7 0
3 years ago
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