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madam [21]
4 years ago
12

Alcl3+Na =NaCl+ Al .did Al change oxidation number

Chemistry
1 answer:
saul85 [17]4 years ago
5 0

Answer:

yes it is ( From +3 to 0 )

Explanation:

If this is the balanced equation:

AlCl3     +    3Na ——>    3NaCl      +      Al

Al      Cl        3Na             Na     Cl            Al

+3     -3        0                    +1       -1            0

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the universe formed through the big bang explosion, all of the elements on Earth have been cooked for billions of years in stars and then released in the universe through super- nova explosions.

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If a cloud holding the most water vapor it possibly can suddenly cools what will occur
valentina_108 [34]
Tiny water droplets or humidity

5 0
3 years ago
Read 2 more answers
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

8 0
3 years ago
the empirical formula for a compound used as a green paint pigment is C2H3As3Cu2O8. The molar mass of its molecular formula was
melisa1 [442]

Answer:

Molecular formula = C₄H₆As₆Cu₄O₁₆

Explanation:

Given data:

Empirical formula = C₂H₃As₃Cu₂O₈

Molar mass of compound = 1013 g/mol

Molecular formula = ?

Solution:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  of C₂H₃As₃Cu₂O₈ is 506.897 g/mol

by putting values.

n = 1013 / 506.897

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₂H₃As₃Cu₂O₈)

Molecular formula = C₄H₆As₆Cu₄O₁₆

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3 years ago
Select whether the statement is for Speed, Velocity, or Acceleration.
Vesna [10]

Answer:

I think that the statement is relative to speed because it is saying km per second.

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