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agasfer [191]
2 years ago
15

Please help fast thanks

Chemistry
1 answer:
timurjin [86]2 years ago
7 0

Answer:

I do not know if I am correct but I think it is the letter D I hope it helps you if it is correct pls brainliests

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When backpacking in the wilderness, hikers often boil water to sterilize it for drinking. Suppose that you are planning a backpa
Pavlova-9 [17]

Answer:

2.104 L fuel

Explanation:

Given that:

Volume of water = 35 L = 35 × 10³ mL

initial temperature of water = 25.0 ° C

The amount of heat needed to boil water at this temperature can be calculated by using the formula:

q_{boiling} = mc \Delta T

where

specific heat   of water c= 4.18 J/g° C

q_{boiling} = 35 \times 10^{3} \times \dfrac{1.00 \ g}{1 \ mL} \times 4.18  \ J/g^0 C \times (100 - 25)^0 C

q_{boiling} = 10.9725 \times 10^6 \ J

Also; Assume that the fuel has an average formula of C7 H16 and 15% of the heat generated from combustion goes to heat the water;

thus the heat of combustion can be determined via the expression

q_{combustion} =-  \dfrac{q_{boiling}}{0.15}

q_{combustion} =-  \dfrac{10.9725 \times 10^6 J}{0.15}

q_{combustion} = -7.315 \times 10^{7} \ J

q_{combustion} = -7.315 \times 10^{4} \ kJ

For heptane; the equation for its combustion reaction can be written as:

C_7H_{16} + 11O_{2(g)} -----> 7CO_{2(g)}+ 8H_2O_{(g)}

The standard enthalpies of the  products and the reactants are:

\Delta H _f   \ CO_{2(g)} = -393.5 kJ/mol

\Delta H _f   \ H_2O_{(g)} = -242 kJ/mol

\Delta H _f   \ C_7H_{16 }_{(g)} = -224.4 kJ/mol

\Delta H _f   \ O_{2{(g)}} = 0 kJ/mol

Therefore; the standard enthalpy for this combustion reaction is:

\Delta H ^0= \sum n_p\Delta H^0_{f(products)}- \sum n_r\Delta H^0_{f(reactants)}

\Delta H^0 =( 7  \ mol ( -393.5 \ kJ/mol)  + 8 \ mol (-242 \ kJ/mol) -1 \ mol( -224.4 \ kJ/mol) - 11  \ mol  (0 \ kJ/mol))

\Delta H^0 = (-2754.5 \ \  kJ -  1936 \ \  kJ+224.4 \  \ kJ+0 \ \  kJ)

\Delta H^0 = -4466.1 \ kJ

This simply implies that the amount of heat released from 1 mol of C7H16 = 4466.1 kJ

However the number of moles of fuel required to burn 7.315 \times 10^{4} \ kJ heat released is:

n_{fuel} = \dfrac{q}{\Delta \ H^0}

n_{fuel} = \dfrac{-7.315 \times 10^{4} \ kJ}{-4466.1  \ kJ}

n_{fuel} = 16.38  \ mol \ of \ C_7 H_{16

Since number of moles = mass/molar mass

The  mass of the fuel is:

m_{fuel } = 16.38 mol \times 100.198 \ g/mol}

m_{fuel } = 1.641 \times 10^{3} \ g

Given that the density of the fuel is = 0.78 g/mL

and we know that :

density = mass/volume

therefore making volume the subject of the formula in order to determine the volume of the fuel ; we have

volume of the fuel = mass of the fuel / density of the fuel

volume of the fuel = \dfrac{1.641 \times 10^3 \ g }{0.78  g/mL} \times \dfrac{L}{10^3 \ mL}

volume of the fuel  = 2.104 L fuel

3 0
3 years ago
I need the answer for the first question 1.
sp2606 [1]

metal salt acid hydroyon and why cuz I guessed and I haven't t learned this yet and I need points

4 0
3 years ago
Calculate the theoretical yield of ammonia produced by the reaction of 100g of H2 gas and 200g of N2 gas
ipn [44]
To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
                     = 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles 
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
                      = 14.28 * 17 = 242.76 g
6 0
3 years ago
PLEASE ANSWER ASAP
Sergio [31]

Answer:

Low level (altitude) clouds that are wispy and made of ice crystals.

precipitation and surface runoff

Hail

Nitrogen

Stratosphere

Decreases

Please Award Brainliest!

7 0
2 years ago
Read 2 more answers
Which statement explains how the Sun influences movement in the Earth's atmosphere?
MakcuM [25]
Correct Answer: The Sun heats the Earth unevenly; this heating pattern then causes convection currents in the atmosphere.
4 0
3 years ago
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