Answer:
Step-by-step explanation:
eq. of any line withslope 1/6 is
y=1/6x+c
∵ it passes through (-2,7)
so 7=1/6(-2)+c
c=7+1/3=22/3
eq. of line is
y=1/6x+22/3
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
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Answer:
see below
Step-by-step explanation:
f(x) = 5x^3 +1, g(x) = – 2x^2, and h(x) = - 4x^2 – 2x +5
f(-8) = 5(-8)^3 +1 = 5 *(-512) +1 =-2560+1 =-2559
g( -6) = -2 ( -6) ^2 = -2 ( 36) = -72
h(9) = -4( 9)^2 -2(9) +5 = -4 ( 81) -18+5 = -324-18+5=-337
