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faust18 [17]
3 years ago
7

I need help. Is this true 0.37<0.3​

Mathematics
2 answers:
nasty-shy [4]3 years ago
5 0

Answer:

0.37<0.3 is false.

Step-by-step explanation:

0.3 = 0.30 and so,

0.37<0.30

is false since 0.37 is greater than 0.30 by a value of 0.07.

leva [86]3 years ago
3 0
That is false. .37>.3
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After robbing a bank in dodge city, a robber gallops off at 14 mi/h. 20 minutes later, the marshall leaves to pursue the robber
Morgarella [4.7K]

For this case we have to write the equation of the position of each one.

We have then:

For the robber:

r = 14t

For the marshall :

r = 16 (t- (\frac{20}{60}))

r = 16 (t-\frac{1}{3})

By the time the marshall reaches the robber we have:

14t = 16 (t-\frac{1}{3})

From here, we clear the time.

We have then:

16t - 14t = \frac{16}{3}

2t = \frac{16}{3}

t =\frac{8}{3}

t = 2.7 h

Answer:

it takes the marshall to catch up to the robber about 2.7 hours.

4 0
3 years ago
Put these in order from least to greatest!: 88/25, 3.551, 3.88, 3 11/20
DedPeter [7]

Rewrite all 4 numbers as decimals to compare them:

88/25 = 3.52

3 11/20 = 3.55

Now arrange them in the correct order:

88/25, 3 11/20, 3.551, 3.88

7 0
3 years ago
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Hey there! I will give you brainliest, 5/5 rating, and thanks if you can answer this one question!
Varvara68 [4.7K]

Hello!

Let's solve this equation for y first.

-10x+y=4

Add 10x to both side.

y=10x+4

Now, let's plug in our x-values to find y.

x: -2, -1, 0, 1, 2

y:-16,-6, 4,14,24

I hope this helps!

8 0
3 years ago
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1
dangina [55]

The way to write this expression in mathematics is A'∩B

<h3>How to solve for the expression</h3>

In order to get the right way to write this expression we have to break it down in two parts.

First we are told that some of the elements are not in A.

This is represented as A'.

Then we are told that they are in the set B. Hence we have it written as B.

Then the expression  not in set A but are in set B would be written as

A'∩B.

Read more on sets here:

brainly.com/question/13458417

#SPJ1

5 0
2 years ago
How to solve by factoring 16x^=121
VMariaS [17]
-------------------------------------------------------
Equation Given :
-------------------------------------------------------
16x² = 121

-------------------------------------------------------
Take away 121 from both sides:
-------------------------------------------------------
16x² - 121 = 0

-------------------------------------------------------
Make each term a perfect square
--------------------------------------------------------
(4x)² - (11)² = 0

--------------------------------------------------------
Apply algebraic rule : a² - b² = (a + b)(a - b)
--------------------------------------------------------
(4x + 11) (4x - 11) = 0

-------------------------------------------------------
Apply zero product property :
-------------------------------------------------------
4x + 11 = 0 or 4x - 11 = 0

--------------------------------------------------------
Solve for x :
--------------------------------------------------------
4x = - 11 or 4x = 11
x = -11/4 or x =11/4

--------------------------------------------------------------------------
Answer: x = -11/4 or x = 11/4
--------------------------------------------------------------------------
5 0
4 years ago
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