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agasfer [191]
3 years ago
8

Izzy runs on the schools track team. She runs 4 3/5 miles in 2/3 hour. What is Izzy's speed in miles per hour?

Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0

With fractions its very easy to get 1 as a whole numer (Which is what were trying to find. ONE miles o we know how much is per hour (one hour)). All you need to do is multiply the 2/3 hour by 3/2. The numers switched. You do this with both variables, the 3/5 miles and the 2/3 hour. After this the hour variable should have turned into a 1 if done correctly. Then we multilly the miles variable by 3/2. when done correctly we get the answer of 6 9/10 miles.

After you've done this, you then know your answer. every 1 hour Izzy runs 6 9/10 miles.

Another way of saying this is Izzy runs 6.9 miles an hour or 6.9mph.

<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>.</u></em><em><u> </u></em><em><u>please</u></em><em><u> </u></em><em><u>consider</u></em><em><u> </u></em><em><u>making</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>Im</u></em><em><u> </u></em><em><u>trying</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>hardest</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>provide</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>answer</u></em><em><u>!</u></em><em><u> </u></em><em><u>Happy</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>

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Answer:

  ∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

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