I don’t understand this but:
The mean is the average of all the numbers combined
the median is the number centered directly in the middle with the same number of numbers on both sides of the number in the middle
The mode is how many times a number appears
Answer: 9/12, 2/12
Step-by-step explanation:
Start by writing multiples of 6 and 4
4: 4, 8, 12
6: 6, 12, 18
Did you see the multiple that both numbers have? Yup, it's 12. So that has to be your denominator for both fractions. This is because you have to have the <u>LEAST</u> COMMON Denominator (LCD). So both numbers have 12 in common as one of their multiples and, it's the least common one because there are no numbers that come before it that are common for both numbers. Now, you just have to change the denominators of both fractions into 12. To do that to 3/4, just multiply the top and bottom by 3 to get 9/12. To do that to 1/6, just multiply the top and bottom by 2 to get 2/12. Hope this helps!
NOTE: REMEBER THAT WHATEVER YOU DO TO THE TOP OF A FRACTION, YOU HAVE TO DO IT TO THE BOTTOM TOO (AND VICE VERSA)
Answer:
x has to be -3 for the answer to be 0
Step-by-step explanation:
Wa=0.5Wb, Ha=20, Hb is unkown
the area of rectangle a is : Wa*20
the area of rectangle b is : Wb*Hb
Rectangle a has 7 times the area of rectangle b: Wa*20=7*Wb*Hb
Replace Wa with 0.5Wb: 0.5Wb*20=7Wb*Hb => Hb=10/7
First mug holds the most
<em><u>Solution:</u></em>
Given that,
You are choosing between two mugs
<em><u>The volume of cylinder is given as:</u></em>
Where,
r is the radius and h is the height
<em><u>One has a base that is 5.5 inches in diameter and a height of 3 inches</u></em>
Therefore,
Also, h = 3 inches
<em><u>Thus volume of cylinder is given as:</u></em>
Thus first mug holds 71.24 cubic inches
<em><u>The other has a base of 4.5 inches in diameter and a height of 4 inches</u></em>
h = 4 inches
Therefore,
Thus the second mug holds 63.585 cubic inches
On comparing, volume of both mugs,
Volume of first mug > volume of second mug
First mug holds the most
