M∠A′B′C′ = m∠ABC would be the answer for this. if you could give me a pic, I could answer. I don't see Triangle ABC
Answer:
16/15
Step-by-step explanation:
Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
20
Step-by-step explanation:
1449÷72.45=20
Answer: Both A, and C
Step-by-step explanation:
The answer to the first system of equations (2x+2y=16) would be
x=3 and y=5 ( 3x-y=4 )
Which means we have to find out which of the other equations has an x value of 3, and a y value of 5.
If A is 2x+2y=16, then x=3 and y=5
6x-2y=8
If B is x+y=16, then x=5 and y=11
3x-y=4
If C is 2x+2y=16, then x=3 and y=5
6x-2y=8
If D is 6x+6y=48 , then x=-2 and y=10
6x+2y=8
Both A and C are equal to the first system of equations, which means they are both correct answers.