False. For every x in the function's domain, f(x) describes the one single output.
Answer:
Step-by-step explanation:
Rearrange each function to solve for x.
Switch x and y,
The resulting equation is the inverse function.
A:
f(x) = y = 5+x
x = y-5
y = x-5
f⁻¹(x) = x-5
g(x) = 5-x ≠ f⁻¹(x)
g(x) is not the inverse of f(x).
:::::
B:
f(x) = y = 2x-9
x = (y+9)/2
y = (x+9)/2
f⁻¹(x) = (x+9)/2
g(x) = (x+9)/2 = f⁻¹(x)
g(x) is the inverse of f(x).
:::::
C:
f(x) = y = 2/x - 6
x = 2/(y+6)
y = 2/(x+6)
f⁻¹(x) = 2/(x+6)
g(x) = (x+6)/2 ≠ f⁻¹(x)
:::::
D:
f(x) = y = x/3 + 4
x = 3y - 12
y = 3x - 12
f⁻¹(x) = 3x - 12
g(x) = 3x - 4 ≠ f⁻¹(x)
g(x) is not the inverse of f(x).
Answer:
J=12
Step-by-step explanation:
(2/3)*j = 8 // - 8
(2/3)*j-8 = 0
2/3*j-8 = 0 // + 8
2/3*j = 8 // : 2/3
j = 8/2/3
j = 12
2x+4-3/2x= 1/3(x+5
3x+1 it needs a lot of time
Answer: C
Step-by-step explanation:
πr^2 is how you find area
r=1/2(d)
r=1/2(12)
r=6
6^2=36
36π
