<span><span><span>Given <span>f(x) = 2x + 3</span><span> and </span><span>g(x) = –x2 + 5</span><span>, find </span></span><span>(<span> f</span> </span>o<span> f )(x</span><span>).</span></span><span>(<span> f</span> </span>o<span> <span>f </span>)(x) = f (<span> f</span> (x))</span><span>
</span><span> = f (2x + 3)</span><span>
</span><span> = 2( ) + 3 </span>... setting up to insert the input<span>
</span><span> = 2(2x + 3) + 3</span><span>
</span><span> = 4x + 6 + 3</span><span>
</span> <span>= 4x + 9</span></span><span><span><span><span>Given </span><span>f(x) = 2x + 3</span><span> and </span><span>g(x) = –x2 + 5</span><span>, find </span></span><span>(g</span><span> o</span><span> g)(x</span><span>).</span></span><span>(g </span>o<span> g)(x) = g(g(x))</span><span>
</span><span> = –( )2 + 5 </span>... setting up to insert the input<span>
</span><span> = –(–x2 + 5)2 + 5</span><span>
</span><span> = –(x4 – 10x2 + 25) + 5</span><span>
</span><span> = –x4 + 10x2 – 25 + 5</span><span>
</span><span> = </span><span>–x4 + 10x2 – 20</span></span>
Sometimes you have to be careful with the domain and range of the composite function.
<span><span><span>Given </span><span>f (x) = sqrt(x)</span><span> and </span><span>g(x) = x – 2</span><span>, find the domains of </span><span>(<span> f</span> </span>o<span> g)(x)</span><span> and </span><span>(g </span>o<span> f )(x)</span>.</span></span>
Answer:
The real solutions are
![x=\sqrt[6]{6}\approx 1.35\\\\\:x=-\sqrt[6]{6}\approx -1.35](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B6%5D%7B6%7D%5Capprox%201.35%5C%5C%5C%5C%5C%3Ax%3D-%5Csqrt%5B6%5D%7B6%7D%5Capprox%20-1.35)
Step-by-step explanation:
The solution, or root, of an equation is any value or set of values that can be substituted into the equation to make it a true statement.
To find the real solutions of the equation 
:
![\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x^6}{5}=\frac{30}{5}\\\\\mathrm{Simplify}\\\\x^6=6\\\\\mathrm{For\:}x^n=f\left(a\right)\mathrm{,\:n\:is\:even,\:the\:solutions\:are\:}x=\sqrt[n]{f\left(a\right)},\:-\sqrt[n]{f\left(a\right)}\\\\x=\sqrt[6]{6}\approx 1.35\\\\\:x=-\sqrt[6]{6}\approx -1.35](https://tex.z-dn.net/?f=%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D5%5C%5C%5C%5C%5Cfrac%7B5x%5E6%7D%7B5%7D%3D%5Cfrac%7B30%7D%7B5%7D%5C%5C%5C%5C%5Cmathrm%7BSimplify%7D%5C%5C%5C%5Cx%5E6%3D6%5C%5C%5C%5C%5Cmathrm%7BFor%5C%3A%7Dx%5En%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%2C%5C%3An%5C%3Ais%5C%3Aeven%2C%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5Bn%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A-%5Csqrt%5Bn%5D%7Bf%5Cleft%28a%5Cright%29%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B6%5D%7B6%7D%5Capprox%201.35%5C%5C%5C%5C%5C%3Ax%3D-%5Csqrt%5B6%5D%7B6%7D%5Capprox%20-1.35)
Answer:
Biff's tree is 14 m off the ground and Rocco's tree is 7 m off the ground.
Step-by-step explanation:
Let the height of Biff's tree be represented by x, so that the height of Rocco's tree is 
.
Draw a straight line from Rocco's point of view to a point t to the middle of Biff's tree. This line divides x into two equal parts, and the angle is divided into 
each.
By alternate angle property,
Tan = 
= Tan × 10
= 7.00021
⇒ x = 2 × 7.0021
= 14. 0042
x = 14
Therefore, Biff's tree is 14 m off the ground and Rocco's tree is 7 m off the ground.
Step-by-step explanation:
Since there are 4 people who answered that they had 0 number of scarves we put 4 0's in a set of numbers. Then we see that there are 2 people who have 1 scarf. so there are 2 1's and we keep on going down the line.
{0,0,0,0,1,1,2,3,3,4,5,5} there are 12 numbers here
so we add up all of them
1+1+2+3+3+4+5+5=24
then divide that number by 12 because that's how many numbers there are
24/12=2
The mean of the numbers is 2
Hope that helps :)
Answer:
4.2
Step-by-step explanation:
surface area of a cube
6l
