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garik1379 [7]
3 years ago
11

Solve the equation. 7x2 – 34x - 5=0

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer: x = -1/7 = -0.143

 x = 5

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I have to repost this because the first time I was not giving correct answers.
SSSSS [86.1K]

Answer and Step-by-step explanation:

We are given: 18x - 2(3x + 1) = 5x - 16

First, lets distribute the -2 to the 3x and 1.

18x - 6x - 2 = 5x - 16

Now, we combine like terms.

12x - 2 = 5x - 16

Next, we add 2 to each side.

12x = 5x -14

Now, we subtract 5x from both sides.

7x = -14

Finally, we divide by 7 on both sides.

x = -2

  Statements:                             Reasons:

  18x - 2(3x + 1) = 5x - 16            Given

  18x - 6x - 2 = 5x - 16                Distributive Property of Equality

  12x - 2 = 5x - 16                       Combine like terms

  12x = 5x -14                              Addition Property of Equality

  7x = -14                                     Subtraction Property of Equality

  x = -2                                        Division Property of Equality

#teamtrees #WAP (Water And Plant)

8 0
3 years ago
Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
Solve the system of equations using substitution. Write the solution as an ordered pair.
IrinaK [193]

Answer:

  (-3, 3)

Step-by-step explanation:

Substitute for y:

  x+6 = -2x -3

  3x = -9 . . . . . . . add 2x -6 to both sides

  x = -3 . . . . . . . . divide by 3

  y = (-3) +6 = 3 . . substitute for x in the first equation

The solution is ...

  (x, y) = (-3, 3)

4 0
3 years ago
Find the ratio of the area inside the square but outside the circle to the area of the square in the picture
Eduardwww [97]

Answer:

0.2146

Step-by-step explanation:

From the picture:

The radius of the circle = r. This means that the area of the circle = πr²

Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²

The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²

The ratio of the area inside the square but outside the circle to the area of the square =  r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146

5 0
3 years ago
If x is 5, then 6x =<br> 5x<br> 30x<br> 30
Wittaler [7]

Answer:

30

Step-by-step explanation:

If X is 5, then 6X is equal to 30. You can see to be able to get 30, you have to multiply 6 to X, which in this case is 5. So 6 times 5, you will now get the answer which is 30.

4 0
3 years ago
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