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bearhunter [10]
3 years ago
9

ANYONE KNOW HOW TO DO THIS?! DON'T LEAVE ME HANGING! I HAVE PICTURE ATTACHED! CAN SOMEBODY PLEASE SHOW ME HOW TO DO THIS! I'M DO

ING A UNIT TEST AND NEED HELP ASAP!
This figure shows circle O with chords PM and LN .

mPL=10∘
mLM=14∘
mLN=24∘
PM=15 in.

What is LN?

Mathematics
2 answers:
aleksandrvk [35]3 years ago
7 0
If you find the answer hmu plz doing the same test
mrs_skeptik [129]3 years ago
4 0

Answer:

ln is equal to pm?  

Step-by-step explanation:

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9. Choose the correct answer.
denpristay [2]

Answer:

what the h3ll type of question is this ?-

Step-by-step explanation:

your never gonna get one because you dont have any so the probability is 0%.

6 0
3 years ago
Five point six times four point eight
LenaWriter [7]

Answer:

26.88

Step-by-step explanation:start eight times four is 32

and than eight times six is 48 than add a zero and do four times six is 24

and four times five is twenty add it up and line up the decimal points

hope i helped !!

3 0
3 years ago
If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
PLEASE I BEG OF YOU HELP ME!!!!! I'm not good at fractions!
Xelga [282]

Answer:

1 1/3 tubs per min.

2 mph.

50 mph.

9 cups per bag.

Step-by-step explanation:

Multiply the numerator of the first number by the denominator of the second number, then divide the product by the denominator of the first number. Hope this helps :)

3 0
3 years ago
How many terms are in this expression?<br><br> -2b^3 - 7c^2 - 10
Maslowich

Answer:

lkfklfkkfjfjdfklfklfklfkfdkfdkldf

Step-by-step explanation:

7 0
3 years ago
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