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Talja [164]
3 years ago
5

PLSSS HELP!!!!! Rewrite in simplest terms: 7(8h+6k)+9k-9(-5k-6h)

Mathematics
2 answers:
Yuki888 [10]3 years ago
5 0

Answer:

110h + 96k

Step-by-step explanation:

Law Incorporation [45]3 years ago
4 0
Wen ate here a couple times a month ago
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Count by fives from 135!to 175 describe the pattern
irina1246 [14]
5 10 15 20 25 30 35 40 45 50 55 60 64 70 75 80 85 90 95 100, 105 110 115 120 125 130 (135) 150 155 160 165 170 (175)
 Five multiplied each number.

Hope I helped!

-RainyClouds~
5 0
3 years ago
M is inversely proportional to r if m= 9 when r= 4 find m when r=2
bazaltina [42]

m=18 when r = 2.

Step-by-step explanation:

Given,

m∝\frac{1}{r}

So,

m = k×\frac{1}{r},--------eq 1, here k is the constant.

To find the value of m when r = 2

At first we need to find the value of k

Solution

Now,

Putting the values of m=9 and r = 4 in eq 1 we get,

9 = \frac{k}{4}

or, k = 36

So, eq 1 can be written as m= \frac{36}{r}

Now, we put r =2

m = \frac{36}{2}

or, m= 18

Hence,

m=18 when r = 2.

4 0
3 years ago
Como convertir la oración en una ecuación algebraica
zimovet [89]

Ok, entonces creo que sería -6 porque -6 x 3 = -16, no estoy seguro de si esto ayudará o te confundirá más, pero ten un buen día

6 0
3 years ago
Solve for theta <br> Please answer both parts
Vika [28.1K]

Answer:

Step-by-step explanation:

a)  tanθ = x/3

θ = arctan(x/3)

:::::

b)  cosθ = 9/x

θ = arccos(9/x)

4 0
3 years ago
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
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