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4 years ago

Which ions remain in solution after pbi2 precipitation is complete? express your answers as ions separated by a comma?

Chemistry

1 answer:

olga nikolaevna [1]4 years ago

7 0

Answer;

K+ and NO3- ions

Explanation;

The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.

However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.

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3 years ago

For a trip to the Moon, a rocket must lift off from

VLD [36.1K]

Answer:

20 m/s^2

Explanation:

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3 years ago

What is the purpose of adding 0. 1% agar to the trypticase nitrate broth when conducting the nitrate reduction test?.

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Agar is used to assist establish an anaerobic environment that promotes nitrate reduction.

Nitrate Reduction test:

The nitrate in the broth is converted to nitrite by organisms that can produce the nitrate reductase enzyme, which can then be further converted to nitric oxide, nitrous oxide, or nitrogen.
Anaerobic respiration and denitrification are two processes that can convert nitrate to a variety of compounds.
While denitrification only reduces nitrate to molecular nitrogen, anaerobic respiration employs nitrate as the bacterium's final electron acceptor, reducing it to a range of chemicals.
The nitrate reduction test is based on the detection of nitrite and its capacity to produce a red precipitate (prontosil), which is a water-soluble azo dye, when it combines with sulfanilic acid to create a complex (nitrite-sulfanilic acid).

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1 year ago

Which of the following generally determines if a reaction will occur?

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Answer:

D - Thermodynamics

Explanation: I just took the quiz

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2 years ago

Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing

Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of $AgNO_3$ = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of $AgNO_3$ = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and $AgNO_3$ .

$\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles$

$\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag$

From the balanced reaction we conclude that

As, 2 mole of $AgNO_3$ react with 1 mole of $Zn$

So, 0.1479 moles of $AgNO_3$ react with $\frac{0.1479}{2}=0.07395$ moles of $Zn$

From this we conclude that, $Zn$ is an excess reagent because the given moles are greater than the required moles and $AgNO_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Ag$