A banana and baking soda in a bag!
I agree with top guy C. and C makes most sense and sorry if I am wrong
Answer:
The provided question is incomplete as it lack essential information and the option however the complete question with correct option are given below:
<em>Egg provides 400 mg of methionine per 100 g of weight.
</em>
<em>The meal that the scientists provided the volunteers at t = 10 hours contained five eggs weighing 500 g each. Approximately how much methionine was served to each volunteer? A. 10 mg
, B. 1 x 104 mg, C. 3 x 104 mg
, D. 6.25 x 105 mg</em>
The correct answer is option B. 1 x 104 mg.
Explanation:
This question is provided the information that an egg gives 400 mg/100 g of the weight. One can calculate methionine that was served to the volunteers as given below:
So, an egg provides 400 mg of methionine per 100 g of weight.
5 eggs = 500 g each weighs in at 2.5 kg total (5 egg x 500 g/egg = 2,500 g).
2,500 g x (400 mg Met/100 g weight) = 10,000 mg = 1.0 x 104 mg
Thus, the correct answer is option B. 1.0 x 104 mg.
Answer: 2. ![NO_2](https://tex.z-dn.net/?f=NO_2)
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
a) If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of N = 30.4 g
Mass of O= 69.6 g
Step 1 : convert given masses into moles
Moles of N=![\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{30.4g}{14g/mole}=2.2moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%20of%20N%7D%7D%7B%5Ctext%7B%20molar%20mass%20of%20N%7D%7D%3D%20%5Cfrac%7B30.4g%7D%7B14g%2Fmole%7D%3D2.2moles)
Moles of O=![\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{69.6g}{16g/mole}=4.4moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%20of%20O%7D%7D%7B%5Ctext%7B%20molar%20mass%20of%20O%7D%7D%3D%20%5Cfrac%7B69.6g%7D%7B16g%2Fmole%7D%3D4.4moles)
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For N = ![\frac{2.2}{2.2}=1](https://tex.z-dn.net/?f=%5Cfrac%7B2.2%7D%7B2.2%7D%3D1)
For O =![\frac{4.4}{2.2}=2](https://tex.z-dn.net/?f=%5Cfrac%7B4.4%7D%7B2.2%7D%3D2)
The ratio of N: O = 1; 2
Hence the empirical formula is ![NO_2](https://tex.z-dn.net/?f=NO_2)
Answer:
yellow
if not sorry that's though the best answer
Explanation: