<em>In the late 1800's, experiments using cathode ray tubes led to the discovery of the;</em>
Electron(s)
<u>It was founded that many different metals release cathode rays, and that cathode rays were made of electrons, very small negatively charged particles.</u>
The compound given (i.e. 3,3-dimethyl-1-butanol) is primary alcohol (1°) because the functional group (-OH) shows that it is alcohol is attached to a primary carbon (i.e terminal carbon).
The oxidation of all primary alcohols results in the formation of aliphatic aldehyde(also known as alkanal).
Suppose, it is secondary alcohol;
The oxidation of secondary alcohol results in the formation of ketone(also known as alkanone).
When 3,3-dimethyl-1-butanol undergoes oxidation, the suffix "ol" in the alcohol changes to "al"
Therefore, 3,3-dimethyl-1-butanol changes to 3,3-dimethyl-1-butanal after undergoing oxidation.
In conclusion, the product when 3,3-dimethyl-1-butanol undergoes oxidation is: 3,3-dimethylbutanal.
As such, option 2 is correct.
Learn more about oxidation reaction here:
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Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.