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3 years ago

Any skilled chemists want to give me some backup?

Chemistry

1 answer:

AleksAgata [21]3 years ago

8 0

Answer:

SO2, HCI and NH3

Explanation:

these three compounds vary inversely with the temperature

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3. What volume would be occupied by 3.5 mol of oxygen gas at a pressure

ruslelena [56]

Answer:

The oxygen will occupied 84.7 L.

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case:

P= 768 mmHg
V= ?
n= 3.5 mol
R= 62.36 $\frac{mmHg*L}{mol*K}$
T= 25 C= 298 K (being 0 C= 273 K)

Replacing:

768 mmHg* V= 3.5 mol* 62.36 $\frac{mmHg*L}{mol*K}$ *298 K

Solving:

$V=\frac{3.5 mol*62.36\frac{mmHg*L}{mol*K}*298 K }{768 mmHg}$

V= 84.7 L

The oxygen will occupied 84.7 L.

3 0

3 years ago

Which mixture can be separated through filtration because one the substances is insoluble in water?

Oduvanchick [21]

B)Na2SO4 and SrSO4 is the answer

6 0

4 years ago

How would you detect sulphur in organic compounds

natita [175]

Answer:

sodium fusion is changed to sodium sulphide if sulphur is present in the compound

8 0

3 years ago

What is the [h3o ] for a solution of seawater at 25°c that has a ph of 8.3?

Kipish [7]

PH of solution at 25ºC = 8.3

$[ H_3O^+] = 10 ^{-pH}$

${H_3O^+] = 10 ^{-8.3}$

$[H_3O^+] = 5.011*10^{-9} M$

hope this helps!

6 0

3 years ago

HELP!! b. At the equivalence point, all of the acid has been neutralized by the base. Why does the pH change so

CaHeK987 [17]

At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.

3 0

3 years ago