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never [62]
3 years ago
11

If 0 lies in the quadrant IV. What can be the value of cos 0?​

Mathematics
2 answers:
marissa [1.9K]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Since Θ is in the fourth quadrant where cosΘ > 0

The only positive values are B / D

since 0 < cosΘ < 1

\frac{\sqrt{41} }{5} > 1 then

D is the appropriate response

OLga [1]3 years ago
3 0

Answer:

D

Step-by-step explanation:

option A and B can not be because square root of 41 is irrational number option C can not be because in 4th quadrant cos is positive so option D is correct.

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2/3y=-3x-9 pleaseeeeeeeeee
charle [14.2K]
The slope is -4.500
Hope this helped :)
3 0
3 years ago
find the length of the line segment with end points (7,2) and (-4,2) explain how you arrived at your solution
Inga [223]

Answer:

<h2>11 units</h2>

Step-by-step explanation:

Method 1:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (7, 2) and (-4, 2). Substitute:

d=\sqrt{(2-2)^2+(-4-7)^2}=\sqrt{0^2+(-11)^2}=\sqrt{11^2}=11

Method 2:

Look at the picture. Mark points in the coordinate system.

Read the length of the segment.

6 0
3 years ago
A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that
mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, H_0 : p = 0.5

Alternate Hypothesis, H_A : p \neq 0.5

(a) The significance level of the test which is represented by \alpha is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

            P(Type I error) = \alpha

         P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0}  +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}  = \alpha

(1\times 1\times 0.5^{10})  +(1 \times 0.5^{10} \times 0.5^{0}) = \alpha

\alpha = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - \beta).

So, here, X ~ Binom(n = 10, p = 0.1)

1-\beta = P(X = 0/H_0 is true) + P(X = 10/H_0 is true)

1-\beta = \binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0}  +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}  

1-\beta = (1\times 1\times 0.9^{10})  +(1 \times 0.1^{10} \times 0.9^{0})

1-\beta = 0.3487

Hence, the power of the test is 0.3487.

3 0
3 years ago
What is the difference between the greatest green bean weight and the least green bean weight.
igor_vitrenko [27]
The Bigger weight minus the lower weight
8 0
3 years ago
Find an equation for the line tangent to the circle x^2 +y^2=25 at the point (3, -4)
Lostsunrise [7]
Hello : 
the center of this cercle is : O( 0, 0)
calculate the slope  m of the line : OA    .. A (3,-4)
m= (yA - yO) / (xA- xO) 
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1   (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)

7 0
3 years ago
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