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erastova [34]
3 years ago
10

Find the complete factored form of the polynomial: 18m² – 14n^3

Mathematics
2 answers:
almond37 [142]3 years ago
8 0

Answer:

Go to this website and see if what you are looking for is on here :)

Step-by-step explanation:

https://www.wolframalpha.com/input/?i=18m²+–+14n%5E3

seropon [69]3 years ago
7 0

Answer:

2

Step-by-step explanation:

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The circumference of a circle is 18.84 meters. what is the circles area
Fed [463]
The area is about 28.25m²
5 0
4 years ago
Use a proportion to determine the number of children age 5 in a kindergarten class if 80% of a class of 20 children are that age
igor_vitrenko [27]

Answer:

16 children

Step-by-step explanation:

80% of 20 children comes out to 16 children who are of age 5.

If desired, rewrite "80%" as "0.80" and use that 0.80 as the multiplier of 20:

0.80(20 children) = 16 children.

4 0
4 years ago
The area of a cylinder's base is 706.5 square millimeters. The cylinder's lateral area is 471 square millimeters. What is the to
Rzqust [24]
Just add the two bases plus the lateral area. so it would be 706.5+706.5+471.
8 0
3 years ago
Read 2 more answers
The product of a number and -3, increased by 8, is 20
natita [175]

answer:

-4

Step-by-step explanation:

-3x+8= 20

-8 -8

-3x = 12

÷-3. = ÷-3

x = -4

3 0
3 years ago
The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the
VLD [36.1K]
We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12

By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192

When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))

Since P(B|A) does not equal to P(B), event A and event B are not independent.

Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>

4 0
3 years ago
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