a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
2 tens & 15 ones is equal to 35
Because 2 tens = 20
15 already has a ten so add +10 to 20
30+5 is 35.
Recall your d = rt, distance = rate * time.
now, let's say she lives "d" miles away, and so if Billy goes say at "r" mph fast to her house, he gets there in 1hr.
now, if he goes 20 mph slower, namely " r - 20 " mph, he gets there in 2 hours, same "d" miles.
Answer:
The answer is the second one
The statement is not always true.
For Example...
The LCM of 6 and 8 is not the product of the two numbers
6*8= 48
48 is not the LEAST common multiple
Multiples of 6 are...
6,12,18,24,30,36,42,48...
Multiples of 8 are....
8,16,24,32,40,48...
The least common multiple is 24 not 48 even though they are both common multiples.