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2 years ago

(-8,-5) after a translation right 1 units and down 5 units?

Mathematics

1 answer:

lara [203]2 years ago

4 0

(-7,0), on a graph plot (-8,-5), from that point you’ll move right once, and go down 5

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The school jazz band consists of 2 male percussionists, 2 female percussionists, 3 male woodwinds, 2 female woodwinds, 4 male br

dusya [7]

Answer:

$\frac{1}{8}$ chance or 12.5% chance

Step-by-step explanation:

2 male percussionists

2 female percussionists

3 male woodwinds

2 female woodwinds

4 male brass players

3 female brass players

We're looking for a female woodwind. Now there is only 2 of them so we get the female woodwinds out of all the jazz band members or $\frac{2}{16}$ or $\frac{1}{8}$ or 12.5% chance.

6 0

3 years ago

The school that Michael goes to is selling tickets to a dance. On the first day of ticket sales the school sold 3 staff tickets

Minchanka [31]

The price of a staff ticket and the price of a student ticket is $8 and $14

Given:

Day 1:

Number of staff tickets sold = 3

Number of students tickets sold = 1

Total revenue day 1 = $38

Day 2:

Number of staff tickets sold = 3

Number of students tickets sold = 2

Total revenue day 2 = $52

let

cost of staff tickets = x

cost of students tickets = y

The equation:

3x + y = 38 (1)

3x + y = 38 (1)3x + 2y = 52 (2)

subtract (1) from (2)

2y - y = 52 - 38

y = 14

substitute y = 14 into (1)

3x + y = 38 (1)

3x + 14 = 38

3x = 38 - 14

3x = 24

x = 24/3

x = 8

Therefore,

cost of staff tickets = x

= $8

cost of students tickets = y

= $14

brainly.com/question/22940808

8 0

2 years ago

Aeva is selling friendship pins as a service project. Each pin with green beads sells for $3. Each pin with red beads sells for

Luba_88 [7]

Answer:69

Step-by-step explanation:

69•2= 138

69-11=58

58•3=174

174+138=312

6 0

3 years ago

Read 2 more answers

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

Please help! Thank you!

Aloiza [94]

Answer:

X=sigma xi/no of observation

5= (?) /4

5*4=sum of all numbers

20=sum of all the observation

If you are helped by this answer pls tag me brianliest I really want it

THANK YOU.......

4 0

2 years ago