Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
Step-by-step explanation:
For a rhombus, the opposite angles are equal:
74=5y+9
5y=65
y=13
For a rhombus, the adjacent angles are supplementary:
74+(z-10)=180
z-10=106
z=116
74+(x+7)=180
x+7=106
x=99
divide $4.50 by 5 .......
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The answer would be D because when you divide 10 by 4 you take one fourth out of ten
