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3 years ago

Imagine a 15 kg block moving with a velocity of 20 m/s to the left. Calculate the kinetic Energy of this block.

Physics

1 answer:

ivann1987 [24]3 years ago

3 0

Answer:

3000 J

Explanation:

Kinetic energy is:

KE = ½ mv²

If m = 15 kg and v = -20 m/s:

KE = ½ (15 kg) (-20 m/s)²

KE = 3000 J

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All of the following are regulated by the medulla except

Fantom [35]

Answer:

D. flight or flight response.

Explanation:

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3 years ago

Cuales son las carreras de velocidad de medio fondo y fondo?

sammy [17]

Answer:

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Explanation:

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2 years ago

A battery connects to a resistor. The rate of energy dissipated by the resistor is 1.44 W. The rate of energy supplied by the ba

wel

Answer:

Explanation:

We have given energy dissipated through the resistor = 1.44 watt

We have to find the energy supplied by the battery

From Telegence theorem we know that energy dissipated through resistor is equal to the energy supplied

As energy supplied is given as 1.44 watt

So energy supplied by the battery will be equal to 1.44 watt

So option (c) will be correct answer

3 0

3 years ago

Prove law of conservation of momentum ,??

ziro4ka [17]

Explanation:

$\law \: of \: conservation \: of \: momentum)$

$\frac{initial}{m1u1 + m2u2} = \frac{fi}{m 2u2}$

<h3>BEFORE COLLISION)  INITIAL MOM. OF BODY A </h3>

PiA = m1u1

After collision) .................. B I. e piB = m2u2

<h2>FINÅL MOMENTUM OF BØDY A I. e PfA= m1v1</h2>

FINAL .......... B I. e PfB = m2v2

ùr ãñswer ✌️

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7 0

3 years ago

300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me

Mandarinka [93]

Answer:

6KW

Explanation:

The computation is shown below:

We know that

Work done= m ×g× h

Here

W= 300×10×10

= 30000 J

= 30 KJ

And

Power= Work done ÷time taken

P = 30000 ÷ 5

= 6000W

= 6KW

The above represent the answer

3 0

2 years ago