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s2008m [1.1K]
2 years ago
5

An archer wants to hit a target that is dropped from a tower. At the sound of a horn, the archer is to shoot an arrow; at the sa

me instant, the target will be dropped. Ignoring air resistance, where should the archer aim in order to hit the target?
A. slightly above the initial position of the object


B. at the spot where the archer hopes to hit the target


C. directly at the initial position of the object


D. above the spot where the archer hopes to hit the target
Physics
2 answers:
MrRissso [65]2 years ago
7 0

Answer:

C. directly at the initial position of the object

Explanation:

As we know that archer wants to hit the target at a given position but at the same time when archer shot the arrow the the target is also dropped under gravity

So here the arrow will move simultaneously in two directions

a) horizontal motion with uniform speed

b) motion under gravity

so here the arrow will move under gravity and drops the same distance in same time as that the target will drop due to gravity

so here the motion of arrow will hit the target if the archer initial shot at the initial position of the target

bija089 [108]2 years ago
6 0

It has to be D because the arrow will drop as it moves, if it were a gun, you'd lead the target so fire below it, but due to it being an arrow, you aim high not low. Also, they didnt specify how fast anything is, so you'd probably miss if you actually did it.


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4 0
2 years ago
In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w
maks197457 [2]
No spacecraft has been built yet that was able to absorb harmful
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4 0
3 years ago
A block of mass m = 1.00 kg is attached to a spring of force constant k = 500 N/m. The block is pulled to a position xi= 5.00 cm
8_murik_8 [283]

Answer:

The speed of the block is 4.96 m/s.

Explanation:

Given that.

Mass of block = 1.00 kg

Spring constant = 500 N/m

Position x_{i}=5.00\ cm

Coefficient of friction = 0.350

(A). We need to calculate the speed the block has as it passes through equilibrium if the horizontal surface is friction less

Using formula of kinetic energy and potential energy

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2-\mu mgx

Put the value into the formula

\dfrac{1}{2}\times1.00\times v^2=\dfrac{1}{2}\times500\times(5.00\times10^{-2})-0.350\times1.00\times9.8\times5.00\times10^{-2}

v^2=\dfrac{2\times12.3285}{1.00}

v^2=24.657

v=4.96\ m/s

Hence, The speed of the block is 4.96 m/s.

6 0
2 years ago
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denpristay [2]

Answer:

1:4

Explanation:

The formula for calculating kinetic energy is:

KE=\dfrac{1}{2}mv^2

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

3 0
3 years ago
Give an example for each of the following, where the force:
max2010maxim [7]

Explanation:

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7 0
2 years ago
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