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s2008m [1.1K]
3 years ago
5

An archer wants to hit a target that is dropped from a tower. At the sound of a horn, the archer is to shoot an arrow; at the sa

me instant, the target will be dropped. Ignoring air resistance, where should the archer aim in order to hit the target?
A. slightly above the initial position of the object


B. at the spot where the archer hopes to hit the target


C. directly at the initial position of the object


D. above the spot where the archer hopes to hit the target
Physics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

C. directly at the initial position of the object

Explanation:

As we know that archer wants to hit the target at a given position but at the same time when archer shot the arrow the the target is also dropped under gravity

So here the arrow will move simultaneously in two directions

a) horizontal motion with uniform speed

b) motion under gravity

so here the arrow will move under gravity and drops the same distance in same time as that the target will drop due to gravity

so here the motion of arrow will hit the target if the archer initial shot at the initial position of the target

bija089 [108]3 years ago
6 0

It has to be D because the arrow will drop as it moves, if it were a gun, you'd lead the target so fire below it, but due to it being an arrow, you aim high not low. Also, they didnt specify how fast anything is, so you'd probably miss if you actually did it.


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At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

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for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

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we have:

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the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
If chilled coke and hot tea are <br> kept together tea cools down but ko gets warm why<br>​
olga55 [171]
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Hope this helped!
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