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Sladkaya [172]
2 years ago
14

4. A desk with a mass of 10 kg is pushed across a floor with an acceleration of 4 m/s?. What

Physics
2 answers:
tatiyna2 years ago
6 0
40 N. If you’re using F=MA MxA would be 10x4 which would get you 40 N
Savatey [412]2 years ago
5 0

Answer:

Below

Explanation:

All we need to do for this question is to plug in our values and solve!

      Force = mass x acceleration

      Force = 10 kg x 4 m/s^2

     Force = 40 Newtons or 40 N

If your teacher requires you to round to sig figs it would be :

    F = 4 x 10^1 N

Hope this helps!

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It has to be the last one because whenever lights are turned on it decreases because all lights are on at the same time. It's good to just have one light on. It doesn't use as much electricity.
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3 years ago
What is the correct order of the layers' density from lowest density to highest?
Orlov [11]

Answer:

C. crust, mantle, core

Explanation:

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In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
Earning a(n) _________degree will result in you earning approximately 1 million more dollars in your lifetime.
enot [183]

Earning a <em>bachelor's </em><em>degree will result in you earning approximately 1 million more dollars in your lifetime. </em>

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3 years ago
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