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Effectus [21]
2 years ago
9

Which excerpt from The Number Devil best conveys that the author's purpose for writing is to entertain?

Physics
2 answers:
Zielflug [23.3K]2 years ago
8 0
This would most likely be c
pentagon [3]2 years ago
7 0

Answer:

I think it is c

Explanation:

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4.00 kg glass coffee cup is 30.0°C at room temperature. It is then plunged into hot dishwater at a temperature of 90.0°C, as sho
statuscvo [17]

Answer:

Q = 200800 Joules.

Explanation:

Given the following data;

Mass = 4kg

Initial temperature = 30.0°C

Final temperature = 90.0°C

Specific heat capacity of glass = 837 J/kg°C

To find the quantity of heat absorbed;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 30

dt = 60°C

Substituting the values into the equation, we have;

Q = 4*837*60

Q = 200800 Joules.

Therefore, the amount of heat absorbed is 200800 Joules.

8 0
3 years ago
Một vật giao động điều hoà với chu kì T = 3,14s và biên độ A=1m tại thời điểm vật qua VTCB có giá trị là
zhenek [66]
W=2pi/T=>w=2
Vmax=AxW=2x1=2
5 0
2 years ago
Which of the following statements about the nuclear strong force is true?
lisabon 2012 [21]

Answer: 2, the nuclear strong force drops to practically nothing at large distances.

Explanation: The protons and neutrons in the nucleus share subatomic particles called pions. This exchange is what keeps the protons and neutrons stuck together in the nucleus. Despite the strong force being the strongest force, it has a very small range. This is because pions have very short lifespans. So, the strong force would have literally no effect at large distances.

Hope that helped! :)

4 0
3 years ago
What force would be required to accelerate a 1,100kg car to 0.5 m/s2
OlgaM077 [116]

Answer:

the force required to accelerate a 1,100kg car is 550N

5 0
3 years ago
Three capacitors having capacitances of 8.40, 8.40, and 4.20 μFμF, respectively, are connected in series across a 36.0-V potenti
son4ous [18]

Answer:

a)Q=71.4 μ C

b)ΔV' = 10.2 V

Explanation:

Given that

C ₁= 8.7 μF

C₂ = 8.2 μF

C₃ = 4.1 μF

The potential difference of the battery, ΔV= 34 V

When connected in series

1/C = 1/C ₁ + 1/C₂ + 1/C₃

1/ C= 1/8.4 +1 / 8.4 + 1/4.2

C=2.1 μF

As we know that when capacitor are connected in series then they have same charge,Q

Q= C ΔV

Q= 2.1 x 34 μ C

Q=71.4 μ C

b)

As we know that when capacitor are connected in parallel then they have same voltage difference.

Q'= C' ΔV'

C'= C ₁+C₂+C₃        (For parallel connection)

C'= 8.4 + 8.4 + 4.2 μF

C'=21 μF

Q'= C' ΔV'

Q'=3 Q

3 x 71.4= 21 ΔV'

ΔV' = 10.2 V

3 0
3 years ago
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