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Ksenya-84 [330]
4 years ago
11

What is a and b . y=ab^x

Mathematics
1 answer:
VladimirAG [237]4 years ago
4 0

Answer:

a = 4, b = \frac{1}{2}

Step-by-step explanation:

Use any ordered pairs of points from the table.

Substitute into the equation and solve for a and b, that is

Using (0, 4), then

4 = ab^{0} = a

Hence a = 4

Using (2, 1), then

1 = 4b^{2} ( divide both sides by 4 )

b² = \frac{1}{4} ( take the square root of both sides )

b = \frac{1}{2}

Equation is

y = 4(\frac{1}{2}) ^{x}

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Find the simplified form of the expression.Give your an answer in scientific notation. (9x 10^5)(6 x 10^-7)
Tpy6a [65]
(9×10^5)(6×10^-7) = 9×6×10^5×10^-7
=54×10^(5-7)
=54×10^-2
=0,54
4 0
4 years ago
Write a single transformation that maps ABC onto A' B' C'
blsea [12.9K]

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Answer:

  Either of ...

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Step-by-step explanation:

There are at least two ways to express the transformation that maps each coordinate to its opposite.

  1. reflection across the origin: (x, y) ⇒ (-x,-y)

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7 0
3 years ago
Divide 180 in a ratio of 4:5:9
Amiraneli [1.4K]
Ratio in which 180 should be divided is 4:5:9
firstly we need to find the total number of portions 
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when dividing 180 into the respective ratio 4:5:9 the portions are as follows
4 x 10 = 40
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7 0
4 years ago
Read 2 more answers
Find a possible formula for a fourth degree polynomial g that has a double zero at -2, g(4) = 0, g(3) = 0, and g(0) = 12. g(x) =
astraxan [27]
<h2>Answer:</h2>

The possible formula for a fourth degree polynomial g is:

         g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)

<h2>Step-by-step explanation:</h2>

We know that if a polynomial has zeros as a,b,c and d then the possible polynomial form is given by:

f(x)=m(x-a)(x-b)(x-c)(x-d)

Here the polynomial g  has a double zero at -2, g(4) = 0, g(3) = 0.

This means that the polynomial g(x) is given by:

g(x)=m(x-(-2))^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x+2)^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x^2+2^2+2\times 2\times x)(x(x-3)-4(x-3))\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-3x-4x+12)\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-7x+12)\\\\i.e.\\\\g(x)=m[x^2(x^2-7x+12)+4(x^2-7x+12)+4x(x^2-7x+12)]\\\\i.e.\\\\g(x)=m[x^4-7x^3+12x^2+4x^2-28x+48+4x^3-28x^2+48x]\\\\i.e.\\\\g(x)=m[x^4-7x^3+4x^3+12x^2+4x^2-28x^2-28x+48x+48]\\\\i.e.\\\\g(x)=m[x^4-3x^3-12x^2+20x+48]

Also,

g(0)=12

i.e.

48m=12\\\\i.e.\\\\m=\dfrac{12}{48}\\\\i.e.\\\\m=\dfrac{1}{4}

Hence, the polynomial g(x) is given by:

g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)

8 0
3 years ago
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