Answer:
After 2.0 minutes the concentration of N2O is 0.3325 M
Explanation:
Step 1: Data given
rate = k[N2O]
initial concentration of N2O of 0.50 M
k = 3.4 * 10^-3/s
Step 2: The balanced equation
2N2O(g) → 2 N2(g) + O2(g)
Step 3: Calculate the concentration of N2O after 2.0 minutes
We use the rate law to derive a time dependent equation.
-d[N2O]/dt = k[N2O]
ln[N2O] = -kt + ln[N2O]i
⇒ with k = 3.4 *10^-3 /s
⇒ with t = 2.0 minutes = 120s
⇒ with [N2O]i = initial conc of N2O = 0.50 M
ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)
ln[N2O] = -1.101
e^(ln[N2O]) = e^(-1.1011)
[N2O} = 0.3325 M
After 2.0 minutes the concentration of N2O is 0.3325 M
7 moles of oxygen are in the sample.
According to the chemical formula, each mole of nickel tetracarbonyl contains 4 moles of C atoms. Simply convert it into a fraction by putting the original solution in the denominator and the diluted solution in the numerator if you need to determine the concentration ratio between two solutions. The V/n ratio for each gas must be the same if the two gases are at the same temperature and pressure. The volume ratio of two gases at the same temperature and pressure is equal to their molar ratio. The mole ratio of C to O is 1 : 1
Learn more about moles here brainly.com/question/10873665
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Number of neutrons = Atomic mass - Atomic number (number of protons)
Hope that helps!
