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ollegr [7]
4 years ago
6

What is the function of the cell membrain

Chemistry
1 answer:
antiseptic1488 [7]4 years ago
4 0

Answer:

The cell membrane, also known as the plasma membrane, is a double layer of lipids and proteins that surrounds a cell and separates the cytoplasm (the contents of the cell) from its surrounding environment. It is selectively permeable, which means that it only lets certain molecules enter and exit.

Explanation:

You might be interested in
Cuales elementos tienen solo un electrón de valencia ​
aleksley [76]

Answer:

En el caso del sodio, la valencia es 1, ya que tiene un solo electrón de valencia, si pierde un electrón se queda con el último nivel completo.

Explanation:

Grupo de la tabla periódica Electrones de valencia

Grupo 14 (IV) (Grupo del carbono) 4

Grupo 15 (V) (Grupo del nitrógeno ) 5

6 0
3 years ago
How many moles are there in<br> 15 grams of:<br> CaCO3<br> 204 grams of:<br> Al203
DerKrebs [107]

1) moles = mass/mR

CaCO3 Mr = 40 + 12 + (16×3)

= 52 + 48

= 100

mass = 15

so the moles would be 15 ÷ 100

which is 0.15 moles of CaCO3

2) moles = mass ÷ Mr

Mr of Al2O3 = 27 + (16×3)

= 27 + 48

= 75

mass = 204

so the moles would be 204/75 which is 2.72 moles of Al2O3

3 0
3 years ago
What is the method use to separate sand and water​
Slav-nsk [51]

Sand and water can be separated by any of the following methods:

1. Sedimentation and decantation: This method involves the mixture being kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.

2. Filtration: This method involves the mixture being passed through a filter paper (a filter with very fine pores). Sand particles being larger in size are retained by the filter paper and get separated from water.

I hope this helps! :D

7 0
3 years ago
The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force stren
shepuryov [24]

Answer:

The answer to your question is below

Explanation:

Alkane                      Formula                    Boiling point (°C)

Methane                   CH₄                                     -162

Ethane                      CH₃CH₃                               - 89

Propane                    CH₃CH₂CH₃                        - 42

Butane                      CH₃(CH₂)₂CH₃                     - 0.5

Pentane                    CH₃(CH₂)₃CH₃                      36

Hexane                     CH₃(CH₂)₄CH₃                      69

Heptane                    CH₃(CH₂)₅CH₃                      98

Octane                      CH₃(CH₂)₆CH₃                     126

Nonane                     CH₃(CH₂)₇CH₃                      151

Decane                      CH₃(CH₂)₈CH₃                     174

6 0
4 years ago
A 150.0 mL sample of an aqueous solution at 25°C contains 15.2 mg of an unknown nonelectrolyte compound. If the solution has an
inysia [295]

<u>Answer:</u> The molar mass of the unknown compound is 223.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = 8.44 torr

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = 62.3637\text{ L torr }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

8.44torr=1\times M\times 62.3637\text{ L. torr }mol^{-1}K^{-1}\times 298K\\\\M=\frac{8.44}{1\times 62.3637\times 298}=4.54\times 10^{-4}M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 4.54\times 10^{-4}M

Given mass of unknown compound = 15.2 mg = 0.0152 g   (Conversion factor:  1 g = 1000 mg)

Volume of solution = 150.0 mL

Putting values in above equation, we get:

4.54\times 10^{-4}M=\frac{0.0152\times 1000}{\text{Molar mass of unknown compound}\times 150.0}\\\\\text{Molar mass of unknown compound}=\frac{0.0152\times 1000}{150.0\times 4.54\times 10^{-4}}=223.2g/mol

Hence, the molar mass of the unknown compound is 223.2 g/mol

5 0
3 years ago
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