Answer:
Entropy,mass and volume.... I think
Answer:
Cp = 0.093 J.g⁻¹.°C⁻¹
Solution:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 300 J
m = mass = 267 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 12 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 300 J / (267 g × 12 °C)
Cp = 0.093 J.g⁻¹.°C⁻¹
1- Movement
2- Respiration
3- Growth
Answer: The 1st Option. ( 159.7g) On EDG.
Explanation:
Air on a hot day translates to hot air and air on a cold day translates to cold air. The hot air usually have more energy due to particles being more excited by the heat.
