Hint: Try using the Pythagorean thereom to solve it.
Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
1:10:10 is the ratio. 10 pennies in a dime, 10 dimes in a dollar.
Move the variables to one side and the constants to the other
50q - 43 = 52q - 81
50q (-52q) - 43 (+43) = 52q (-52q) - 81 (+43)
50q - 52q = -81 + 43
-2q = -38
isolate the q, divide -2 from both sides
-2q/-2 = -38/-2
q = -38/-2
q = 19
hope this helps
<span>The answer is one. First, these are both straight lines, meaning they will have one intersection point. In order to find the intersections of these two lines, we must set them equal to one another. So x + 5y = 6 equals 3x + 30y = 36. When you solve the two equations together, you'll get one intersection point at (0 , 1.2).</span>
