I got 21/4 hope this helps
Answer:
80%
Step-by-step explanation:
Let's call the past exam mark m,
m*105%=84
m*105/100=84
m=84/(105/100)
m=80
Hope this helps!
Answer:x=0 is the first statement, 3x+2<12 is the greater justification
Step-by-step explanation:
The answer to the problem is:
<span>8j^3 + 5j^2 - 3 - 5j^3 - 7j^2 + 12j - 7
</span>
<span>3j^3 - 2j^2 + 12j - 10
</span>
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Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649