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Musya8 [376]
3 years ago
9

Can someone please help me please?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

\large \mathfrak{Answer : }

The equation of the red parabola is :

  • f(x) = 1 -  {x}^{2}

therefore , correct option in A

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What's 19/30 x 12/16?
mr Goodwill [35]
19/40 as a fraction and decimal it is 0.475
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A 13 ​-ft ladder is leaning against a house when its base starts to slide away. By the time the base is 12 ft from the​ house, t
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I think the answer is B because all the air other answers are incorrect
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2 years ago
The dot plots below show the runs scored in each of the first games of the season by the Hawks and the Eagles. Runs Scored (Ha R
omeli [17]

Answer:

Part B: 8 and 2 (more answers ofc)

Part C: Two more dots on 6 (more than one answer tho)

Step-by-step explanation:

<em>Part B:</em>

The added number of dots is 39 at the beginning and the mean is 3.9. (39/10). Since we have to add 2 dots the equation will be (<em>39 + ? + ?) / 12 = Less than 3.9</em>. We also need the range to increase. This means that one of the blanks must be larger than 7 (the largest dot on the dot plot!) I just went with 8 to keep the mean as small as possible. This leaves 1 more blank to figure out. There are multiple answers to this problem but I went with 2 just because then the mean would be 3.5 a better answer than something like 3.58333333333.

<em>Part C:</em>

If you think about it all the dots added up should be 6x12 = 72. Currently all the dots add up to 60. 72-60 is 12. This means that 12 is equal to 2 dots. I guess you could also do 5 and 7, 8 and 4, etc.

G'day

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4 0
2 years ago
WILL MARK BRAINLIEST TO FIRST CORRECT ANSWER
evablogger [386]

Answer:

{(-1, 8), (0, 5), (2, -1), (3, -4)}

Step-by-step explanation:

I used a calculator, pls let me know if im incorrect

3 0
3 years ago
During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this
alex41 [277]

Answer:

Step-by-step explanation:

Given that during  the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt

Resolve into partial fractions

\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}

Integrate to get

ln P -0.00474/0.0001489  (ln (0.0001489P-0.03135) = t+C

ln P -31.833  (ln (0.0001489P-0.03135) =t+C

\frac{P}{( ( (0.0001489P-0.03135)^{31.833}  } =Ae^t

Limiting population would be infinity.

6 0
3 years ago
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